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In the equation of motion, S=ut+1/2 at^(...

In the equation of motion, `S=ut+1/2 at^(2), s stands for

A

distance in t seconds

B

maximum height reached

C

distance in the `t^(th)` second

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the equation of motion \( S = ut + \frac{1}{2} at^2 \), we need to identify what \( S \) stands for in this context. ### Step-by-Step Solution: 1. **Understanding the Equation**: The equation \( S = ut + \frac{1}{2} at^2 \) is one of the equations of motion used in physics to describe the motion of an object under uniform acceleration. 2. **Identifying the Variables**: - \( S \): This represents the **displacement** of the object. Displacement is the distance moved in a specific direction from the initial position. - \( u \): This is the initial velocity of the object. - \( a \): This is the acceleration of the object. - \( t \): This is the time for which the object has been moving. 3. **Conclusion**: In the equation \( S = ut + \frac{1}{2} at^2 \), \( S \) stands for **displacement**. ### Final Answer: In the equation of motion \( S = ut + \frac{1}{2} at^2 \), \( S \) stands for **displacement**.
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Knowledge Check

  • Following are three equations of motion S(g)=ut+(1)/(2)at^(2) v(s)=sqrt(u^(2)+2as) v(t)=u+at Where ,S,u,t,a,v are respectively the displacement ( dependent variable ) , initial ( constant ) , time taken ( independent variable ) , acceleration ( constant ) and final velocity ( dependent variable ) of the particel after time t . Find the displacement of the particle when its velocity becomes 10m//s if acceleration is 5m//s^(2) all through -

    A
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