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The electrode potential for the Danicell...

The electrode potential for the Danicell given below is 1.1V.
`Zn(s)|Zn^(2+)(aq)||Cu^(2+)(aq)|Cu(s)`
Write overall cell reaction and calculate the standard Gibb's energy for the reaction. `[F=96487c//mol]`.

Text Solution

Verified by Experts

`Zn+Cu^(2+)rarrZn^(2+)+Cu`
`DeltaG^(@)=-nFE_("cell")^(@)`
`=-2xx96487xx1.1`
`=-"212271.4 Joules"`
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(a) The electrode potential for the Daniell cell given below is 1.1 V. Zn(s) |Z_(n)^(2+)(aq)||Cu^(2+)(aq)|Cu(s) Write overall cell reaction and calculate the standard Gibb's energy for the reaction. [ F 96487 c//mol] (b) Mention any two factors which affects the conductivity of electrolytic solution .

For the cell Zn(s)|Zn^(2+) (2M)||Cu^(2+) (0.5 M)|Cu(s) (a) Write equation for each half reaction. (b) Calculate the cell potential at 25^@C

Knowledge Check

  • Zn(s)|Zn^(2+) (aq)||Cu^(2+)(aq) |Cu(s) is (Anode ) (Cathode)

    A
    Weston cell
    B
    Daniel cell
    C
    Calomel cell
    D
    Standard cell

  • The standard electrode potential for Daniell cell is 1.1 volt. What is the standard Gibbs energy for the reaction ?

    A
    `212.3 kJ mol^(-1)`
    B
    `-212.3 kJ mol^(-1)`
    C
    `106.15 kJ mol^(-1)`
    D
    `-106.15 kJ mol^(-1)`

  • The standard electrode potential for Daniel cell is 1.1 volt. What is the standard Gibbs energy for the reaction ?

    A
    212.3 kJ `"mol"^(-1)`
    B
    `-212.3 "kJ mol"^(-1)`
    C
    `106.15 "kJ mol"^(-1)`
    D
    `-106.15 "kJ mol"^(-1)`

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