A particle moves along a circle of radius `[20/pi]` metre with constant tengential acceleration. If the velocity of the particle is 40 m/s at the end of second revolution, Find the tangential acceleration.

Explanation

`v^2 =u^2 + 2as=2 ar theta` ` [thereforeS=rtheta]`
`therefore a=v^2/(2rtheta)` `therefore a= (40xx40)/(2xx20/pi xx4pi)=10 m/s^2`