Home
Class 12
PHYSICS
An AC voltage rating 240V, 50Hz. Find th...

An AC voltage rating 240V, 50Hz. Find the time to change current from max. value to rms value.

A

`2.55 ms`

B

`2.5 ms`

C

`0.25 ms`

D

`25 ms`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the time it takes for the current in an AC circuit to change from its maximum value to its RMS value, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Values:** - AC Voltage (V) = 240V - Frequency (f) = 50Hz 2. **Determine the Maximum Current (I₀):** - The maximum current (I₀) is related to the maximum voltage (V₀) and the impedance (Z) of the circuit. However, since we are not given the impedance, we can focus on the relationship between I₀ and the RMS value. - The RMS current (I_rms) is given by the formula: \[ I_{rms} = \frac{I_0}{\sqrt{2}} \] 3. **Use the AC Current Equation:** - The current in an AC circuit can be expressed as: \[ I(t) = I_0 \sin(\omega t) \] - Where \(\omega\) (angular frequency) is given by: \[ \omega = 2\pi f \] 4. **Set Up the Equation for RMS Current:** - To find the time when the current reaches the RMS value, we set: \[ I(t) = I_{rms} = \frac{I_0}{\sqrt{2}} \] - Substituting this into the current equation gives: \[ I_0 \sin(\omega t) = \frac{I_0}{\sqrt{2}} \] 5. **Simplify the Equation:** - Dividing both sides by \(I_0\) (assuming \(I_0 \neq 0\)): \[ \sin(\omega t) = \frac{1}{\sqrt{2}} \] 6. **Find the Angle Corresponding to RMS Value:** - The angle whose sine is \(\frac{1}{\sqrt{2}}\) is: \[ \omega t = \frac{\pi}{4} \] 7. **Calculate the Time (t):** - Now, substituting \(\omega = 2\pi f\): \[ \frac{\pi}{4} = 2\pi f t \] - Rearranging gives: \[ t = \frac{\pi}{4 \cdot 2\pi f} = \frac{1}{8f} \] 8. **Substituting the Frequency:** - Substituting \(f = 50 \, \text{Hz}\): \[ t = \frac{1}{8 \cdot 50} = \frac{1}{400} \, \text{s} \] 9. **Convert to Milliseconds:** - Converting seconds to milliseconds: \[ t = \frac{1}{400} \, \text{s} = 0.0025 \, \text{s} = 2.5 \, \text{ms} \] ### Final Answer: The time taken for the current to change from its maximum value to its RMS value is **2.5 ms**.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • JEE MAIN 2021

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS SECTION B|30 Videos

Similar Questions

Explore conceptually related problems

A resistance fo 40 Omega is connected to an a.c. source of 220 V, 50 Hz. Find (i) the rms current (ii) maximum instantaneous current in the resistor (iii) time taken by the current to change from max. value to rms value

A 100 Omega iron is connected to an AC source of 220 V 50 Hz . Calculate the time taken by the current to change from its maximum value to rms value .

Knowledge Check

  • An AC source is rated at 220V, 50 Hz. The time taken for voltage to change from its peak value to zero is

    A
    `50 sec`
    B
    `0.02 sec`
    C
    `5 sec`
    D
    `5xx10^(-3)sec`
  • An inductor coil is connected to a 12V battery and drawing a current 24 A. This coil is connected to capacitor and an AC source of rms voltage rating 24 V in the series connection. The rms current through the circuit would found to be

    A
    48 A
    B
    36 A
    C
    0
    D
    24 A
  • Similar Questions

    Explore conceptually related problems

    A resistance of 20 Omega is connected to a source of alternating current rated 110 V, 50 Hz . Find (a) the rms current, (b) the maxium instantaneous current in the resistor and © the time taken by the current to change from its maximum value to the rms value.

    An AC source with V_max = 200V and f=50hz aconnected across 10 ohm resistance. Find the source voltage changes from maximum to rms value.

    Consider an AC supply of 220 V-50 Hz. A resistance of 30 Omega is connected to this source . Find the (a) rms value of current (b) the peak value of current and (c ) the time taken by current to change its value from maximum to rms value .

    In an AC circuit having resistance of 10 Omega . Find the time taken by current to reach RMS value from maximum value. Frequency and RMS voltage of source is 50hz and 220V

    In india we use alternating voltage with rms value of 220 V and frequency 50 Hz. (a) Calculate corresponding peak voltage . (b) What minimum time the voltage takes to change from 0 to rms value ? (c ) What maximum time will it take to become 0 starting from rms value ?

    An AC source rated 220 V, 50 Hz is connected to a resistor. The time taken by the current to change from its maximum to the rms value is :