Taking the Bohr radius as `a_(0)`= 53 pm the radius of `Li^(++)` ion in its ground state, on the basis of Bohr's model, will be about.

Options

A. 53 pm
B. 27 pm
C. 18 pm
D. 13 pm

Answer

C

Explanation

Orbital radius of electron in `n^(th)` orbit of an electron in H-like atoms
`r_(n)=(a_(0)n^(2))/(Z)`
Taking `Z=3` for `Li^(++)` ion and n=1 for its ground state,
`r_(1)=(53)xx((1)^(2))/(3)`
`:. r_(1)(53)xx((1)^(2))/(3)`
`:.r_(1)=17.67` pm
`~~18` pm (picometer)