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Find the equation of the parabola in eac...

Find the equation of the parabola in each of the following cases: vertex at (1,3) and the directrix x+3=0.

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Vertex at (1,3) directrix x+3=0 `therefore` h=1, k=3 we have the directrix is x=h-a `therefore` h-a=3 `therefore` eqn of the parabola `(y-k)^2`=4a(x-h)
`(y-3)^2`=16(x-1)
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