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In post office box experiment, if Q/P=1/...

In post office box experiment, if `Q/P=1/(10)`. In (R ) if ` 142 Omega` is used then we get deflection towards right and if ` R =143 Omega` , then deflection is towards left. What is the range of unknown resistance?

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To solve the problem regarding the unknown resistance in the post office box experiment, we will follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information:** - We have the ratio \( \frac{Q}{P} = \frac{1}{10} \). - When \( R = 142 \, \Omega \), the deflection is towards the right. - When \( R = 143 \, \Omega \), the deflection is towards the left. 2. **Set Up the Wheatstone Bridge Equation:** - In a Wheatstone bridge, at null deflection, the relationship is given by: \[ \frac{Q}{P} = \frac{x}{R} \] - Here, \( x \) is the unknown resistance, and \( R \) is the known resistance. 3. **Calculate Unknown Resistance for \( R = 142 \, \Omega \):** - Substitute the values into the equation: \[ \frac{1}{10} = \frac{x}{142} \] - Rearranging gives: \[ x = \frac{142}{10} = 14.2 \, \Omega \] 4. **Calculate Unknown Resistance for \( R = 143 \, \Omega \):** - Substitute the new value of \( R \): \[ \frac{1}{10} = \frac{x}{143} \] - Rearranging gives: \[ x = \frac{143}{10} = 14.3 \, \Omega \] 5. **Determine the Range of Unknown Resistance:** - From the calculations, we find that when \( R = 142 \, \Omega \), \( x = 14.2 \, \Omega \) and when \( R = 143 \, \Omega \), \( x = 14.3 \, \Omega \). - Therefore, the range of the unknown resistance \( x \) is: \[ 14.2 \, \Omega \leq x < 14.3 \, \Omega \] ### Final Answer: The range of the unknown resistance \( x \) is from \( 14.2 \, \Omega \) to \( 14.3 \, \Omega \). ---

To solve the problem regarding the unknown resistance in the post office box experiment, we will follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information:** - We have the ratio \( \frac{Q}{P} = \frac{1}{10} \). - When \( R = 142 \, \Omega \), the deflection is towards the right. - When \( R = 143 \, \Omega \), the deflection is towards the left. ...
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