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Equation st=u + at - 1/2 a does not seem...

Equation `s_t=u + at - 1/2 a` does not seem dimensionally correct, why?

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To analyze the equation \( s_t = u + at - \frac{1}{2} a \) for dimensional correctness, we will break it down step by step. ### Step 1: Identify the dimensions of each term in the equation 1. **Dimension of \( s_t \)**: - \( s_t \) represents displacement, which has the dimension of length (L). - Dimension: \( [s_t] = L \) 2. **Dimension of \( u \)**: - \( u \) represents initial velocity, which has the dimension of length per time (L/T). - Dimension: \( [u] = L T^{-1} \) 3. **Dimension of \( at \)**: - \( a \) represents acceleration, which has the dimension of length per time squared (L/T²). - \( t \) represents time, which has the dimension of time (T). - Therefore, the dimension of \( at \) is: \[ [at] = [a][t] = (L T^{-2})(T) = L T^{-1} \] 4. **Dimension of \( -\frac{1}{2} a \)**: - This term is a bit misleading because it seems to suggest that we are subtracting acceleration directly. However, we need to consider the context of the equation. - If we consider it as \( -\frac{1}{2} a t^2 \), we can analyze it as follows: - \( a \) has the dimension \( L T^{-2} \) and \( t^2 \) has the dimension \( T^2 \). - Therefore, the dimension of this term is: \[ \left[-\frac{1}{2} a t^2\right] = [a][t^2] = (L T^{-2})(T^2) = L \] ### Step 2: Combine the dimensions of all terms Now, we can rewrite the equation considering the proper dimensions: \[ s_t = u + at - \frac{1}{2} a t^2 \] - The dimensions of \( u \) and \( at \) are both \( L T^{-1} \). - The dimension of \( -\frac{1}{2} a t^2 \) is \( L \). ### Step 3: Check for dimensional consistency In the equation \( s_t = u + at - \frac{1}{2} a t^2 \): - The left-hand side \( s_t \) has the dimension \( L \). - The right-hand side consists of: - \( u \) has dimension \( L T^{-1} \) - \( at \) has dimension \( L T^{-1} \) - \( -\frac{1}{2} a t^2 \) has dimension \( L \) Since \( u \) and \( at \) have dimensions of \( L T^{-1} \), they cannot be added to \( -\frac{1}{2} a t^2 \) which has dimension \( L \). Therefore, the equation as presented is not dimensionally consistent. ### Conclusion The equation \( s_t = u + at - \frac{1}{2} a \) is not dimensionally correct because it combines terms of different dimensions (length and length per time).

To analyze the equation \( s_t = u + at - \frac{1}{2} a \) for dimensional correctness, we will break it down step by step. ### Step 1: Identify the dimensions of each term in the equation 1. **Dimension of \( s_t \)**: - \( s_t \) represents displacement, which has the dimension of length (L). - Dimension: \( [s_t] = L \) ...
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Knowledge Check

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