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x - t equation of a particle in SHM is ...

`x - t` equation of a particle in SHM is
`x = (4 cm)cos ((pi)/(2)t)`
Here ,`t` is in seconds. Find the distance travelled by the particle in first three seconds.

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To find the distance travelled by the particle in the first three seconds, we can follow these steps: ### Step 1: Identify the parameters from the given equation The equation of motion for the particle in Simple Harmonic Motion (SHM) is given as: \[ x = 4 \, \text{cm} \cos\left(\frac{\pi}{2} t\right) \] From this equation, we can identify: - Amplitude \( A = 4 \, \text{cm} \) - Angular frequency \( \omega = \frac{\pi}{2} \, \text{rad/s} \) ### Step 2: Determine the period of the motion The period \( T \) of SHM can be calculated using the formula: \[ T = \frac{2\pi}{\omega} \] Substituting the value of \( \omega \): \[ T = \frac{2\pi}{\frac{\pi}{2}} = 4 \, \text{s} \] ### Step 3: Analyze the motion within the first three seconds Since the period \( T \) is 4 seconds, the particle will complete one full oscillation (from \( +A \) to \( -A \) and back to \( 0 \)) in 4 seconds. In the first 3 seconds, the particle will not complete a full oscillation. ### Step 4: Calculate the position of the particle at \( t = 3 \, \text{s} \) We can find the position of the particle at \( t = 3 \, \text{s} \): \[ x(3) = 4 \cos\left(\frac{\pi}{2} \times 3\right) \] \[ x(3) = 4 \cos\left(\frac{3\pi}{2}\right) \] Since \( \cos\left(\frac{3\pi}{2}\right) = 0 \): \[ x(3) = 4 \times 0 = 0 \, \text{cm} \] ### Step 5: Determine the distance travelled The particle starts from its maximum position \( +4 \, \text{cm} \) at \( t = 0 \, \text{s} \) and moves to \( 0 \, \text{cm} \) at \( t = 3 \, \text{s} \). The distance travelled by the particle is: - From \( +4 \, \text{cm} \) to \( 0 \, \text{cm} \): \( 4 \, \text{cm} \) In the first 3 seconds, the particle moves from \( +4 \, \text{cm} \) to \( -4 \, \text{cm} \) and then back to \( 0 \, \text{cm} \), covering: - From \( +4 \, \text{cm} \) to \( -4 \, \text{cm} \): \( 8 \, \text{cm} \) - From \( -4 \, \text{cm} \) to \( 0 \, \text{cm} \): \( 4 \, \text{cm} \) Thus, total distance travelled: \[ \text{Total distance} = 4 + 4 = 12 \, \text{cm} \] ### Final Answer Hence, the distance travelled by the particle in the first 3 seconds is: \[ \text{Distance} = 12 \, \text{cm} \] ---

To find the distance travelled by the particle in the first three seconds, we can follow these steps: ### Step 1: Identify the parameters from the given equation The equation of motion for the particle in Simple Harmonic Motion (SHM) is given as: \[ x = 4 \, \text{cm} \cos\left(\frac{\pi}{2} t\right) \] From this equation, we can identify: - Amplitude \( A = 4 \, \text{cm} \) - Angular frequency \( \omega = \frac{\pi}{2} \, \text{rad/s} \) ...
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Knowledge Check

  • The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.

    A
    a. 4 m
    B
    b. 8 m
    C
    c. 12 m
    D
    d. 16 m
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