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A particle is subjected to two simple ha...

A particle is subjected to two simple harmonic motions of the same frequency and direction. The amplitude of the first motion is `4.0 cm` and that of the second is `3.0 cm`. Find the resultant amplitude if the phase difference between the two motion is
(a) `0^(@)`
(b) `60^(@)`
( c) `90 ^(@)`
(d) `180^(@)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
In such situation, amplitudes are added by vector method.
`A_(R) = sqrt((4)^(2) + (3)^(2) + 2(4)(3)cos phi)`
`= sqrt(25 + 24cos phi)` ...(i)
Now, we can substitute different values of `phi` given in different parts in the question and can find the value of `A_(R)`.
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