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An air column in a pipe, when is closed ...

An air column in a pipe, when is closed at one end, is in resonance with a vibrating tuning fork of frequency `264 H_(Z)`. If `upsilon = 330 m//s`, the length of the column in cm is (are) a) 31.25 b) 62.50 c) 93.75 d) 125

A

`31.25`

B

`62.50`

C

`93.75`

D

`125`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the length of the air column in a pipe that is closed at one end, which is in resonance with a tuning fork of frequency 264 Hz. The speed of sound in air is given as 330 m/s. ### Step-by-Step Solution: 1. **Understand the Resonance Condition**: For a pipe closed at one end, the fundamental frequency (first harmonic) occurs when there is one quarter of a wavelength in the pipe. The relationship between frequency (f), speed of sound (v), and wavelength (λ) is given by: \[ f = \frac{v}{\lambda} \] For the fundamental mode in a closed pipe: \[ L = \frac{\lambda}{4} \] 2. **Relate Wavelength to Frequency**: Rearranging the formula for frequency gives us: \[ \lambda = \frac{v}{f} \] 3. **Substituting for Wavelength**: Substitute the expression for wavelength into the length formula: \[ L = \frac{1}{4} \cdot \frac{v}{f} \] 4. **Plug in the Values**: Now we can substitute the known values into the equation: - \( v = 330 \, \text{m/s} \) - \( f = 264 \, \text{Hz} \) \[ L = \frac{1}{4} \cdot \frac{330}{264} \] 5. **Calculate the Length**: First, calculate \( \frac{330}{264} \): \[ \frac{330}{264} = 1.25 \] Now, calculate \( L \): \[ L = \frac{1.25}{4} = 0.3125 \, \text{m} \] 6. **Convert to Centimeters**: Since the question asks for the length in centimeters, convert meters to centimeters: \[ L = 0.3125 \, \text{m} \times 100 = 31.25 \, \text{cm} \] 7. **Consider Higher Harmonics**: For higher harmonics (n = 3), the length can be calculated as: \[ L = \frac{3 \cdot v}{4f} = \frac{3 \cdot 330}{4 \cdot 264} \] Calculate: \[ L = \frac{990}{1056} = 0.9375 \, \text{m} = 93.75 \, \text{cm} \] ### Final Answer: The lengths of the column in resonance with the tuning fork are: - **31.25 cm** (for n = 1) - **93.75 cm** (for n = 3) Thus, the correct options are: - a) 31.25 cm - c) 93.75 cm

To solve the problem, we need to determine the length of the air column in a pipe that is closed at one end, which is in resonance with a tuning fork of frequency 264 Hz. The speed of sound in air is given as 330 m/s. ### Step-by-Step Solution: 1. **Understand the Resonance Condition**: For a pipe closed at one end, the fundamental frequency (first harmonic) occurs when there is one quarter of a wavelength in the pipe. The relationship between frequency (f), speed of sound (v), and wavelength (λ) is given by: \[ f = \frac{v}{\lambda} ...
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