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Calculate the bulk modulus of air from t...

Calculate the bulk modulus of air from the following data about a sound wave of wavelength 35 cm travelling in air. The pressure at a point varies between `(1.0xx 10^5+-14)` Pa and the particles of the air vibrate in simple harmonic motion of amplitude` 5.5 x 10^-5m.

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To calculate the bulk modulus of air using the provided data about a sound wave, we can follow these steps: ### Step 1: Understand the given data - Wavelength (λ) = 35 cm = 0.35 m - Pressure variation (ΔP) = ±14 Pa (the amplitude of pressure variation) - Amplitude of particle vibration (s₀) = 5.5 x 10⁻⁵ m - Average pressure (P₀) = 1.0 x 10⁵ Pa ### Step 2: Use the formula for bulk modulus The bulk modulus (B) can be calculated using the formula: \[ B = \frac{\Delta P \cdot \lambda}{2 \pi s₀} \] Where: - ΔP is the pressure amplitude - λ is the wavelength - s₀ is the displacement amplitude ### Step 3: Substitute the known values into the formula Substituting the values we have: - ΔP = 14 Pa - λ = 0.35 m - s₀ = 5.5 x 10⁻⁵ m So, \[ B = \frac{14 \, \text{Pa} \cdot 0.35 \, \text{m}}{2 \pi (5.5 \times 10^{-5} \, \text{m})} \] ### Step 4: Calculate the numerator Calculate the numerator: \[ 14 \cdot 0.35 = 4.9 \, \text{Pa m} \] ### Step 5: Calculate the denominator Calculate the denominator: \[ 2 \pi (5.5 \times 10^{-5}) \approx 2 \cdot 3.14 \cdot 5.5 \times 10^{-5} \approx 3.46 \times 10^{-4} \, \text{m} \] ### Step 6: Divide the numerator by the denominator Now, divide the numerator by the denominator to find B: \[ B = \frac{4.9}{3.46 \times 10^{-4}} \] ### Step 7: Perform the final calculation Calculating this gives: \[ B \approx 1.42 \times 10^{5} \, \text{N/m}^2 \] ### Conclusion Thus, the bulk modulus of air is approximately: \[ B \approx 1.4 \times 10^{5} \, \text{N/m}^2 \] ---

To calculate the bulk modulus of air using the provided data about a sound wave, we can follow these steps: ### Step 1: Understand the given data - Wavelength (λ) = 35 cm = 0.35 m - Pressure variation (ΔP) = ±14 Pa (the amplitude of pressure variation) - Amplitude of particle vibration (s₀) = 5.5 x 10⁻⁵ m - Average pressure (P₀) = 1.0 x 10⁵ Pa ...
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Calculate the bulk modulus of air from the following data about a sound wave of wavelength 35 cm travelling in air. The pressure at a point varies between (1.0 xx 10^5+-14) Pa and the particles of the air vibrate in simple harmonic motion of amplitude 5.5 xx 10^-6m .

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Knowledge Check

  • A drop of water of radius 0.0015 mm is falling in air .If the cofficient of viscosity of air is 2.0 xx 10^(-5) kg m^(-1)s^(-1) ,the terminal velocity of the drop will be (The density of water = 10^(3) kg m^(-3) and g = 10 m s^(-2) )

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