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One mole of an ideal monoatomic gas is i...

One mole of an ideal monoatomic gas is initially at 300K. Find the final temperature if 200J of heat are added as follows:
(a) at constant volume (b) at constant pressure.

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To solve the problem, we need to find the final temperature of one mole of an ideal monoatomic gas after adding 200 J of heat under two different conditions: at constant volume and at constant pressure. ### (a) At Constant Volume 1. **Identify the formula for heat added at constant volume**: The heat added at constant volume is given by the equation: \[ Q = n C_V \Delta T \] where: - \( Q \) is the heat added (200 J), - \( n \) is the number of moles (1 mole), - \( C_V \) is the molar heat capacity at constant volume for a monoatomic gas, which is \( \frac{3}{2} R \), - \( \Delta T \) is the change in temperature. 2. **Substitute known values**: The value of the gas constant \( R \) is approximately \( 8.31 \, \text{J/(mol K)} \). Thus, we can calculate \( C_V \): \[ C_V = \frac{3}{2} R = \frac{3}{2} \times 8.31 = 12.465 \, \text{J/(mol K)} \] 3. **Set up the equation**: Now we can substitute the values into the heat equation: \[ 200 = 1 \times 12.465 \times (T_f - 300) \] 4. **Solve for \( T_f \)**: Rearranging the equation gives: \[ T_f - 300 = \frac{200}{12.465} \] \[ T_f - 300 = 16.04 \] \[ T_f = 316.04 \, \text{K} \] ### (b) At Constant Pressure 1. **Identify the formula for heat added at constant pressure**: The heat added at constant pressure is given by: \[ Q = n C_P \Delta T \] where: - \( C_P \) is the molar heat capacity at constant pressure for a monoatomic gas, which is \( \frac{5}{2} R \). 2. **Calculate \( C_P \)**: \[ C_P = \frac{5}{2} R = \frac{5}{2} \times 8.31 = 20.825 \, \text{J/(mol K)} \] 3. **Set up the equation**: Substitute the values into the heat equation: \[ 200 = 1 \times 20.825 \times (T_f - 300) \] 4. **Solve for \( T_f \)**: Rearranging gives: \[ T_f - 300 = \frac{200}{20.825} \] \[ T_f - 300 = 9.61 \] \[ T_f = 309.61 \, \text{K} \] ### Final Results - (a) Final temperature at constant volume: **316.04 K** - (b) Final temperature at constant pressure: **309.61 K**

To solve the problem, we need to find the final temperature of one mole of an ideal monoatomic gas after adding 200 J of heat under two different conditions: at constant volume and at constant pressure. ### (a) At Constant Volume 1. **Identify the formula for heat added at constant volume**: The heat added at constant volume is given by the equation: \[ Q = n C_V \Delta T ...
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