Home
Class 12
PHYSICS
Find equivalent capacitance between poin...

Find equivalent capacitance between points `A` and `B`. [Assume each conducting plate is having same dimensions and neglect the thickness of the plate `(epsilon_0A)/d=7muF` where A is area of plate]` `

A

`7muF`

B

`11muF`

C

`12muF`

D

`15muF`

Text Solution

Verified by Experts

The correct Answer is:
B

`C=(epsilon_0A)/d=7muF`
The equivalent circuit is as shown in figure.

`C_(AB)=11/7 C=11/7(7muF)`
`=11muF`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CAPACITORS

    DC PANDEY ENGLISH|Exercise OBJECTIVE_TYPE|1 Videos

  • CAPACITORS

    DC PANDEY ENGLISH|Exercise OBJECTIVE_TYPE|1 Videos

  • ATOMS

    DC PANDEY ENGLISH|Exercise MEDICAL ENTRANCES GALLERY|42 Videos

  • COMMUNICATION SYSTEM

    DC PANDEY ENGLISH|Exercise Subjective|11 Videos

Similar Questions

Explore conceptually related problems

Find out equivalent capacitance between A and B. (take each plate Area = A)

Find the equivalent capacitance between point a and b in the following arrangement of the plates .

Find the equivalent capacitance between A and B . A : area of each plate, d : separation between the plates.

Find out equivalent capacitance between A and B. (take each plate Area = A and distance between two conjugative plates is d)

The equivalent capacitance between P and Q in the figure is (area of each plate is A and separation between two consecutive plates is d)

The equivalent capacitance of the arrangement shown in figure, if A is the area of each plate is

Derive an expression for the capacitance of a parallel plate capacitor in terms of the areas of the plates and the distance between them. Assume there is a vacuum in between the plates with the electric field between the plates E=(sigma)/(epsilon_(0)) (where the symbols have their usual meaning).

Find the capacitance between A and B if three dielectric slabs of dielectric constants K_(1) area A _(2) and thickness d_(2) ) are inserted between the plates of a parallel late capacitor of plate area A. (Given that the distance between the two plates is d_(1)=d_(2)+d_(2) .) .

Find out the capacitance of parallel plate capacitor of plate area A and plate separation d.

Force between two conducting large plates , with charges Q and Q/2 as shown in the figure, is (Area of each face of plate =A)

Home
Profile