Two ends of an inductor of inductance L ...

Two ends of an inductor of inductance `L` are connected to two parallel conducting wires. A rod of length `l` and mass m is gien velocity `v_0` as shown. The whole sytem is placed in perpendicular magnetic field B. Find the maximum current in the inductor. (Neglect gravity and friction)

`(mv_0)/L`

`sqrt(m/L)v_0`

`(mv_0^2)/L`

None of these

Text Solution

Verified by Experts

The correct Answer is:

`1/2mv_0^2=1/2Li_(max)^2`
`:. i_(max)=sqrt(m/L)v_0`

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