Home
Class 12
PHYSICS
Assertion: Two identical waves due to tw...

Assertion: Two identical waves due to two coherent sources interfere at a point with a phase difference of `(2pi)/3`, then the resultant intensity at this point is equal to the individual intensity of the sources.
Reason: A phase difference of `(2pi)/3` is equivalent to a path difference of `lambda/3`.

A

(a)If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.

B

(b)If both Assertion and Reason are true and the Reason is not the correct explanation of the Assertion.

C

(c) If Assertion is true, but the Reason is false.

D

(d) If Assertion is false, but the Reason is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion and the reason provided. ### Step 1: Understanding the Assertion The assertion states that when two identical waves from coherent sources interfere at a point with a phase difference of \( \frac{2\pi}{3} \), the resultant intensity at that point is equal to the individual intensity of the sources. ### Step 2: Formula for Resultant Intensity The resultant intensity \( I \) of two coherent waves can be calculated using the formula: \[ I = 4I_0 \cos^2\left(\frac{\phi}{2}\right) \] where \( I_0 \) is the intensity of each individual wave and \( \phi \) is the phase difference. ### Step 3: Substitute the Phase Difference Given \( \phi = \frac{2\pi}{3} \), we substitute this into the formula: \[ I = 4I_0 \cos^2\left(\frac{2\pi}{3 \cdot 2}\right) = 4I_0 \cos^2\left(\frac{\pi}{3}\right) \] ### Step 4: Calculate \( \cos^2\left(\frac{\pi}{3}\right) \) The value of \( \cos\left(\frac{\pi}{3}\right) \) is \( \frac{1}{2} \). Therefore, \[ \cos^2\left(\frac{\pi}{3}\right) = \left(\frac{1}{2}\right)^2 = \frac{1}{4} \] ### Step 5: Substitute Back to Find Resultant Intensity Now substituting back, we get: \[ I = 4I_0 \cdot \frac{1}{4} = I_0 \] This shows that the resultant intensity \( I \) is indeed equal to the individual intensity \( I_0 \). ### Step 6: Conclusion for Assertion Thus, the assertion is **true**. ### Step 7: Understanding the Reason The reason states that a phase difference of \( \frac{2\pi}{3} \) corresponds to a path difference of \( \frac{\lambda}{3} \). ### Step 8: Path Difference Calculation The relationship between phase difference \( \phi \) and path difference \( \Delta x \) is given by: \[ \Delta x = \frac{\lambda}{2\pi} \cdot \phi \] Substituting \( \phi = \frac{2\pi}{3} \): \[ \Delta x = \frac{\lambda}{2\pi} \cdot \frac{2\pi}{3} = \frac{\lambda}{3} \] This confirms that the reason is also **true**. ### Step 9: Relationship Between Assertion and Reason While both statements are true, the reason does not correctly explain the assertion. The assertion's correctness is derived from the intensity formula, not directly from the path difference. ### Final Answer The assertion is true, the reason is true, but the reason is not the correct explanation for the assertion. Therefore, the answer is option B. ---

To solve the question, we need to analyze both the assertion and the reason provided. ### Step 1: Understanding the Assertion The assertion states that when two identical waves from coherent sources interfere at a point with a phase difference of \( \frac{2\pi}{3} \), the resultant intensity at that point is equal to the individual intensity of the sources. ### Step 2: Formula for Resultant Intensity The resultant intensity \( I \) of two coherent waves can be calculated using the formula: \[ ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • INTERFERENCE AND DIFFRACTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Level 1 Objective|11 Videos
  • INTERFERENCE AND DIFFRACTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Objective question|2 Videos
  • INTERFERENCE AND DIFFRACTION OF LIGHT

    DC PANDEY ENGLISH|Exercise Exercise 32.2|6 Videos
  • GRAVITATION

    DC PANDEY ENGLISH|Exercise All Questions|135 Videos
  • MAGNETIC FIELD AND FORCES

    DC PANDEY ENGLISH|Exercise Medical entrance s gallery|59 Videos

Similar Questions

Explore conceptually related problems

When two waves of intensities l_1 and l_2 coming from coherent sources interfere at a point P, where phase difference is phi , then resultant intensity (l_(res)) at point P would be

Two sound waves having a phase difference of 60^(@) have path difference of

Knowledge Check

  • In Young's double slit experiment two disturbances arriving at a point P have phase difference fo (pi)/(3) . The intensity of this point expressed as a fraction of maximum intensity I_(0) is

    A
    `(3)/(2)I_(0)`
    B
    `(1)/(2)I_(0)`
    C
    `(4)/(3)I_(0)`
    D
    `(3)/(4)I_(0)`
  • Similar Questions

    Explore conceptually related problems

    If two sources have a randomly varying phase difference f(t), the resultant intensity will be given by:

    Two monochromatic light waves of amplitude 3A and 2A interfering at a point have a phase difference of 60^(@) . The intensity at that point will be proportional to:

    Two light sources with intensity I_(0) each interfere in a medium where phase difference between them us (pi)/2 . Resultant intensity at the point would be.

    It is found that what waves of same intensity from two coherent sources superpose at a certain point, then the resultant intensity is equal to the intensity of one wave only. This means that the phase difference between the two waves at that point is

    Two coherent sources each emitting light of intensity I_(0) Interfere, in a medium at a point, where phase different between them is (2pi)/3 . Then, the resultant intensity at that point would be.

    Assertion: Three waves of equal amplitudes interfere at a point. Phase difference between two successive waves is pi/2 . Then, resultant intensity is same as the intensity due to individual wave. Reason: Two different light sources are never coherent.

    Two coherent sources of different intensities send waves which interfere. The ratio of maximum intensity to the minimum intensity is 25. The intensities of the sources are in the ratio