Home
Class 11
PHYSICS
Assertion In projectile motion, if time ...

Assertion In projectile motion, if time of flight is made two times, then maximum height will become four times.
Reason `T prop sin theta` and `H prop sin^(2) theta`, where `theta` is angle of projection.

A

If both Asseration and Reason are correct and Reason is the correct explanation of Assertion

B

If both Assertion and Reason are correct but Reason is not the correct explanation of Assertion

C

If Assertion is true but Reason is false

D

If Assertion is false but Reason is true

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOTION

    DC PANDEY ENGLISH|Exercise Medical entrance|12 Videos
  • MOTION

    DC PANDEY ENGLISH|Exercise Match the Columns|4 Videos
  • MOTION

    DC PANDEY ENGLISH|Exercise Taking it together|96 Videos
  • MEASUREMENT AND ERRORS

    DC PANDEY ENGLISH|Exercise Subjective|19 Videos
  • MOTION IN A PLANE

    DC PANDEY ENGLISH|Exercise (C )Medical entrances gallery|32 Videos

Similar Questions

Explore conceptually related problems

Assertion In projectile motion, if time of flight is 4s, then maximum height will be 20 m. (Take, g = 10 ms^(-2)) Reason Maximum height = (gT)/(2) .

Assertion : If time of flight in a projectile motion is made two times, its maximum height will become four times. Reason : In projectile motion H prop T^2 , where H is maximum height and T the time of flight.

Knowledge Check

  • The relation between the time of flight of projectile T_(f) and the time to reach the maximum height t_(m) is

    A
    `T_(f) = 2t_(m)`
    B
    `T_(f) = t_(m)`
    C
    `T_(f) = (t_(m))/(2)`
    D
    `T_(f) = sqrt(2)(t_(m))`
  • The horizontal range of projectile is 4sqrt(3) times the maximum height achieved by it, then the angle of projection is

    A
    `30^(@)`
    B
    `45^(@)`
    C
    `60^(@)`
    D
    `90^(@)`
  • What is the relationship between time of flight T and horizontal range R? (where theta is angle of projection with the horizontal)

    A
    `R=(gT)/(tantheta)`
    B
    `R=(gT^2)/(2tantheta)`
    C
    `R=(gT^2)/(tantheta)`
    D
    `R=(gT)/(2 tan theta)`
  • Similar Questions

    Explore conceptually related problems

    Find the angle of projection for a projectile motion whose rang R is (n) times the maximum height H .

    Assertion: In projectile motion, when horizontal range is n times the maximum height, the angle of projection is given by tan theta=(4)/(n) Reason: In the case of horizontal projection the vertical increases with time.

    Assertion : Range of projectile of projection of a body is made n times . Its time of fights becomes n times . Reason Range of jprojectile does not depend on the initial velocity of a body .

    If T is the total time of flight, h is the maximum height and R is the range for horizontal motion, the x and y coordinates of projectile motion and time t are related as

    A projectile has a time of flight T and range R . If the time of flight is doubled, keeping the angle of projection same, what happens to the range ?