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in the given figure, alpha=15m//s^(2) re...

in the given figure, `alpha=15m//s^(2)` represents the total accleration of a particle moving in the clockwise direction on a circle radius R = 2.5m aat a given of time The speed of the particle is

A

`4.5`m/w

B

`5.0` m/s

C

`5.7` m/s

D

`6.2`m/s

Text Solution

Verified by Experts

The correct Answer is:
C
Centripetal acceleration of a particle moving on a circular path is given by
`a_(C)=(V^(2))/(R)`
In the given figure,
`a_(C)=a cos 30^(@)=15 cos 30^(@)ms^(-2)`
`rArr" "(v^(2))/(R)=15 cos 30^(@)`
`rArr" "v^(2)=Rxx15xx(sqrt3)/(2)=2.5xx13xx(sqrt3)/(2)`
`therefore" "v=5.7ms^(-1)`
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