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Electric field intensity at a point in b...

Electric field intensity at a point in between two parallel sheets with like charges of same surface charge densities `(sigma)` is

A

`(sigma)/(2epsi_(0))`

B

`(sigma)/(epsi_(0))`

C

zero

D

`(2 sigma)/(epsi_(0))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the electric field intensity at a point between two parallel sheets with like charges of the same surface charge density (σ), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Configuration**: We have two parallel sheets, both having the same surface charge density (σ). The sheets can either be both positively charged or both negatively charged. 2. **Electric Field Due to a Single Sheet**: The electric field (E) due to an infinite plane sheet with surface charge density σ is given by the formula: \[ E = \frac{\sigma}{2\epsilon_0} \] where ε₀ is the permittivity of free space. 3. **Direction of Electric Field**: - If the sheets are positively charged, the electric field due to each sheet points away from the sheet. - If the sheets are negatively charged, the electric field due to each sheet points towards the sheet. 4. **Calculating the Electric Field Between the Sheets**: - For two positively charged sheets: - The electric field due to the first sheet (E₁) at a point between the sheets points away from the sheet. - The electric field due to the second sheet (E₂) also points away from it. - Therefore, both fields add up in the region between the sheets: \[ E_{\text{net}} = E_1 + E_2 = \frac{\sigma}{2\epsilon_0} + \frac{\sigma}{2\epsilon_0} = \frac{\sigma}{\epsilon_0} \] - For two negatively charged sheets: - The electric field due to the first sheet points towards it. - The electric field due to the second sheet also points towards it. - Thus, the fields again add up in the region between the sheets: \[ E_{\text{net}} = E_1 + E_2 = \frac{\sigma}{2\epsilon_0} + \frac{\sigma}{2\epsilon_0} = \frac{\sigma}{\epsilon_0} \] 5. **Conclusion**: Since both cases (positive and negative charges) yield the same result, we conclude that the electric field intensity at a point between two parallel sheets with like charges of the same surface charge density is: \[ E_{\text{net}} = \frac{\sigma}{\epsilon_0} \] ### Final Answer: The electric field intensity at a point between two parallel sheets with like charges of the same surface charge density (σ) is: \[ E = \frac{\sigma}{\epsilon_0} \]
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Knowledge Check

  • Two large parallel conducting plates are placed close to each other ,the inner surface of the two plates have surface charge densities +sigma and -sigma .The outer surfaces are without charge.The electric field has a magnitude of

    A
    ``(sigma)/(epsi_(0))` in the region between the plates
    B
    ''`(sigma)/(epsi_(0))` in the region between the plates
    C
    0
    D
    none of these
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