The work done in bringing a `20` coulomb charge from point `A` to point `B` for disatnce `0.2 m` is `2 J`. The potential difference between the two points will be (in volt)

Options

A. 0.2
B. 8
C. 0.1
D. 0.4

Answer

To find the potential difference between two points A and B when a charge is moved, we can use the formula that relates work done (W), charge (Q), and potential difference (ΔV):

1. **Identify the formula**: The work done in moving a charge in an electric field is given by the equation:
\[ W = Q \times \Delta V \]
where:
- \( W \) is the work done (in joules),
- \( Q \) is the charge (in coulombs),
- \( \Delta V \) is the potential difference (in volts).

2. **Rearrange the formula to find potential difference**: We can rearrange this equation to solve for the potential difference:
\[ \Delta V = \frac{W}{Q} \]

3. **Substitute the known values**: From the problem, we know:
- Work done, \( W = 2 \) joules,
- Charge, \( Q = 20 \) coulombs.

Now, substituting these values into the rearranged formula:
\[ \Delta V = \frac{2 \, \text{J}}{20 \, \text{C}} \]

4. **Calculate the potential difference**:
\[ \Delta V = \frac{2}{20} = 0.1 \, \text{V} \]

Thus, the potential difference between points A and B is **0.1 volts**.