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The value of gravitation is G = 6.67 xx ...

The value of gravitation is `G = 6.67 xx 10^(-11)N-m^(2)/(kg^(2))` in SI units . Convert it into CGS system of units .

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To convert the gravitational constant \( G = 6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \) from SI units to CGS units, we will follow these steps: ### Step 1: Understand the SI Units The SI unit of the gravitational constant is given as: \[ G = 6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \] where: ...
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The value of gravitation is G = 6.67 xx 10^(-11)N-m^(2)/kg^(2) in SL units . Convert it into CGS system of units .

If the value of universal gravitational constant is 6.67xx10^(-11) Nm^2 kg^(-2), then find its value in CGS system.

Knowledge Check

  • The value of universal gravitational constant G=6.67xx10^(-11)Nm^(2)kg^(-2) . The value of G in units of g^(-1)cm^(3)s^(-2) is

    A
    `6.67xx10^(-8)`
    B
    `6.67xx10^(-7)`
    C
    `6.67xx10^(-9)`
    D
    `6.67xx10^(-10)`
  • Similar Questions

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    If in a system the force of attraction between two point masses of 1kg each situated 1km apart is taken as a unit force and is called notwen (newton written in reverse order) If G = 6.67 xx 10^(-11) N-m^(2)kg^(-2) in \SI units, the relation of newton and nowton is

    What is the work done in taking an object of mass 1kg from the surface of the earth to a height equal to the radius of the earth ? ( G = 6.67 xx 10^(-11) Nm^(2)//Kg^(2) , Radius of the earth = 6400 km, Mass of the earth = 6 xx 10^(24) kg .)

    A satellite revolve round a planet in an orbit just above the surface of a planet. Taking G = 6.67 xx 10^(-11) Nm^(2) kg^(2) and mean density of the planet 5.51 xx 10^(3) kg//m^(3) find the period of the planet.

    A satellite of mass 50kg orbits the earth at a height of 100km. Calcualte (i) K.E. (ii) P.E. and (iii) total energy . Given G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) . Radius of the arth is 6400 and mass of the earth is 6 xx 10^(24) kg.

    The radius of the earth is 6.37 xx 10^(6) m and its mean density is 5.5 xx 10^(3) "kg m"^(-3) and G = 6.67 xx 10^(-11) "N-m"^(2) kg^(-2) Find the gravitational potential on the surface of the earth.

    N. m^(-1) is the S.I unit of

    Assuming the earth b to be a homogeneous sphere determine the density of the earth from the following data. g = 9.8 m//s^(2), G = 6.67 xx 10^(-11) Nm^(2) kg^(2) , radius of the earth = 6372km.