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A body of mass 1 kg begins to move unde...

A body of mass `1 kg` begins to move under the action of a time dependent force `vec F = (2 t hat i + 3 t^(2) hat j) N`, where `hat i` and `hat j` are unit vectors along x-and y-axes. What power will be developed by the force at the time `t` ?

A

`(2t^(2)+4t^(4))W`

B

`(2t^(3)+3t^(4))W`

C

`(2t^(3)+3t^(5))W`

D

`(2t+3t^(3))W`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these steps: ### Step 1: Identify the given information We have: - Mass of the body, \( m = 1 \, \text{kg} \) - Force acting on the body, \( \vec{F} = (2t \hat{i} + 3t^2 \hat{j}) \, \text{N} \) ### Step 2: Write the relationship between force, mass, and acceleration According to Newton's second law, the force acting on an object is equal to the mass of the object multiplied by its acceleration: \[ \vec{F} = m \vec{a} \] Since \( m = 1 \, \text{kg} \), we have: \[ \vec{F} = \vec{a} \] ### Step 3: Relate acceleration to velocity Acceleration can be expressed as the time derivative of velocity: \[ \vec{a} = \frac{d\vec{v}}{dt} \] Thus, we can write: \[ \vec{F} = \frac{d\vec{v}}{dt} \] ### Step 4: Set up the equation for velocity From the force equation, we have: \[ \frac{d\vec{v}}{dt} = 2t \hat{i} + 3t^2 \hat{j} \] To find the velocity, we integrate both sides with respect to time \( t \): \[ d\vec{v} = (2t \hat{i} + 3t^2 \hat{j}) dt \] Integrating: \[ \vec{v} = \int (2t \hat{i} + 3t^2 \hat{j}) dt = (t^2 \hat{i} + t^3 \hat{j}) + \vec{C} \] Assuming the initial velocity is zero, we can ignore the constant of integration \( \vec{C} \): \[ \vec{v} = t^2 \hat{i} + t^3 \hat{j} \] ### Step 5: Calculate power developed by the force Power \( P \) developed by the force is given by the dot product of force and velocity: \[ P = \vec{F} \cdot \vec{v} \] Substituting the expressions for \( \vec{F} \) and \( \vec{v} \): \[ P = (2t \hat{i} + 3t^2 \hat{j}) \cdot (t^2 \hat{i} + t^3 \hat{j}) \] Calculating the dot product: \[ P = (2t \cdot t^2) + (3t^2 \cdot t^3) = 2t^3 + 3t^5 \] ### Step 6: Final expression for power Thus, the power developed by the force at time \( t \) is: \[ P = 2t^3 + 3t^5 \, \text{W} \] ---

To solve the problem step by step, we will follow these steps: ### Step 1: Identify the given information We have: - Mass of the body, \( m = 1 \, \text{kg} \) - Force acting on the body, \( \vec{F} = (2t \hat{i} + 3t^2 \hat{j}) \, \text{N} \) ### Step 2: Write the relationship between force, mass, and acceleration ...
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