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Match the following columns. {:(,"Colu...

Match the following columns.
`{:(,"Column I",,"Column II"),(A.,"Tesla",p,[ML^(2)A^(-2)T^(-2)]),(B.,"Weber",q,[MLA^(-2)T^(-1)]),(C.,"Weber m"^(-2),r.,[MA^(-1)T^(-2)]),(D.,"Henry",s.,"None"):}`

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The correct Answer is:
To solve the problem of matching the units in Column I with their corresponding dimensions in Column II, we will analyze each unit one by one. ### Step-by-Step Solution: 1. **Match Tesla (A)**: - Tesla (T) is the unit of magnetic field. - The formula for the magnetic field (B) is given by: \[ B = \frac{F}{Q \cdot V} \] - Where: - \( F \) (force) has dimensions \( [M^1 L^1 T^{-2}] \) - \( Q \) (charge) is \( I \cdot T \) (current times time), so its dimensions are \( [A^1 T^1] \) - \( V \) (velocity) has dimensions \( [L^1 T^{-1}] \) - Substituting these into the formula: \[ B = \frac{[M^1 L^1 T^{-2}]}{[A^1 T^1] \cdot [L^1 T^{-1}]} = \frac{[M^1 L^1 T^{-2}]}{[A^1 L^1 T^0]} = [M^1 A^{-1} T^{-2}] \] - Therefore, Tesla corresponds to **R**: \( [M^1 A^{-1} T^{-2}] \). 2. **Match Weber (B)**: - Weber (Wb) is the unit of magnetic flux. - The magnetic flux (Φ) is given by: \[ Φ = B \cdot A \] - Where: - \( B \) has dimensions \( [M^1 A^{-1} T^{-2}] \) (as calculated above) - \( A \) (area) has dimensions \( [L^2] \) - Thus, the dimensions for magnetic flux are: \[ Φ = [M^1 A^{-1} T^{-2}] \cdot [L^2] = [M^1 L^2 A^{-1} T^{-2}] \] - This matches with **S**: "None" since there is no corresponding match in Column II. 3. **Match Weber m\(^{-2}\) (C)**: - Weber per square meter (Wb/m²) is equivalent to Tesla (T). - Therefore, the dimensions are the same as those for Tesla: \[ [M^1 A^{-1} T^{-2}] \] - Thus, Weber per square meter also corresponds to **R**. 4. **Match Henry (D)**: - Henry (H) is the unit of inductance. - The inductance (L) is given by: \[ L = \frac{Φ}{I} \] - Where: - \( Φ \) has dimensions \( [M^1 L^2 A^{-1} T^{-2}] \) (as calculated for Weber) - \( I \) (current) has dimensions \( [A^1] \) - Therefore, the dimensions for inductance are: \[ L = \frac{[M^1 L^2 A^{-1} T^{-2}]}{[A^1]} = [M^1 L^2 A^{-2} T^{-2}] \] - This matches with **P**: \( [M^1 L^2 A^{-2} T^{-2}] \). ### Final Matches: - A (Tesla) → R \([M^1 A^{-1} T^{-2}]\) - B (Weber) → S (None) - C (Weber m\(^{-2}\)) → R \([M^1 A^{-1} T^{-2}]\) - D (Henry) → P \([M^1 L^2 A^{-2} T^{-2}]\)

To solve the problem of matching the units in Column I with their corresponding dimensions in Column II, we will analyze each unit one by one. ### Step-by-Step Solution: 1. **Match Tesla (A)**: - Tesla (T) is the unit of magnetic field. - The formula for the magnetic field (B) is given by: \[ ...
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Knowledge Check

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