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The electron in a hydrogen atom makes a...

The electron in a hydrogen atom makes a transition from `n=n_(1)` to `n=n_(2)` state. The time period of the electron in the initial state `(n_(1))` is eight times that in the final state `(n_(2))`. The possible values of `n_(1)` and `n_(2)` are

A

`n_(1)=8,n_(2)=1`

B

`n_(1)=4, n_(2)=2`

C

`n_(1)=2,n_(2)=4`

D

`n_(1)1, n_(2)=8`

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To solve the problem, we need to analyze the relationship between the time period of the electron in different energy states of a hydrogen atom. ### Step-by-Step Solution: 1. **Understanding the Time Period Relation**: The time period \( T \) of an electron in a hydrogen atom is related to the principal quantum number \( n \). The time period can be expressed as: \[ T \propto n^3 \] This means that the time period is directly proportional to the cube of the principal quantum number. 2. **Setting Up the Equation**: According to the problem, the time period of the electron in the initial state \( n_1 \) is eight times that in the final state \( n_2 \): \[ T_1 = 8 T_2 \] Using the proportional relationship, we can write: \[ T_1 = k n_1^3 \quad \text{and} \quad T_2 = k n_2^3 \] where \( k \) is a constant. 3. **Substituting the Time Periods**: Substituting these expressions into the time period equation gives: \[ k n_1^3 = 8 (k n_2^3) \] Simplifying this, we get: \[ n_1^3 = 8 n_2^3 \] 4. **Taking the Cube Root**: Taking the cube root of both sides, we find: \[ n_1 = 2 n_2 \] 5. **Finding Possible Values**: Now we need to find integer values for \( n_1 \) and \( n_2 \) that satisfy this relationship. Since \( n_1 \) must be twice \( n_2 \), we can set \( n_2 = x \) and \( n_1 = 2x \). The principal quantum numbers must be positive integers. Thus, we can choose: - If \( n_2 = 1 \), then \( n_1 = 2 \times 1 = 2 \) - If \( n_2 = 2 \), then \( n_1 = 2 \times 2 = 4 \) - If \( n_2 = 3 \), then \( n_1 = 2 \times 3 = 6 \) - And so on... However, since the problem does not specify a maximum limit for \( n \), we can conclude that the pairs \((n_1, n_2)\) can be: - \( (2, 1) \) - \( (4, 2) \) - \( (6, 3) \) - etc. 6. **Conclusion**: The possible values of \( n_1 \) and \( n_2 \) that satisfy the condition given in the problem are: - \( n_1 = 4 \) and \( n_2 = 2 \) (as one of the valid pairs).

To solve the problem, we need to analyze the relationship between the time period of the electron in different energy states of a hydrogen atom. ### Step-by-Step Solution: 1. **Understanding the Time Period Relation**: The time period \( T \) of an electron in a hydrogen atom is related to the principal quantum number \( n \). The time period can be expressed as: \[ T \propto n^3 ...
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The electron in a hydrogen atom makes a transition n_(1) rarr n_(2) , where n_(1) and n_(2) are the principle quantum numbers of the two states. Assume the Bohr model to be valid. The time period of the electron in the initial state is eight times that in the final state. the possible values of n_(1) and n_(2) are

Knowledge Check

  • The electron in hydrogen atom makes a transition n_(1)ton_(2) where n_1 and n_2 are the principal quantum number of two states. Assuming the Bohr model to be valid, the time period of the electron in the initial state is eight times that in the final state. The possible value of n_1 and n_2 are:

    A
    `n_1=4,n_2=2`
    B
    `n_1=8,n_2=2`
    C
    `n_1=8,n_2=1`
    D
    `n_1=6,n_2=2`
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