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In a Young's double slit experiment, the...

In a Young's double slit experiment, the fringe width will remain same, if ( D = distance between screen and plane of slits, d = separation between two slits and `lambda` = wavelength of light used)

A

Both `lambda` and D are doubled

B

Both d and D are doubled

C

D is doubled but d is halved

D

`lamba` is doubled but d is halved

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To solve the problem regarding the fringe width in a Young's double slit experiment, we need to analyze how changes in the parameters affect the fringe width. The formula for fringe width (β) is given by: \[ \beta = \frac{\lambda D}{d} \] where: - \( \beta \) = fringe width - \( \lambda \) = wavelength of light used - \( D \) = distance between the screen and the plane of the slits - \( d \) = separation between the two slits ### Step-by-Step Solution: 1. **Understand the Formula**: The fringe width is directly proportional to the wavelength (\( \lambda \)) and the distance to the screen (\( D \)), and inversely proportional to the slit separation (\( d \)). 2. **Analyze the Options**: We will check each option to see if the fringe width remains the same (i.e., \( \beta' = \beta \)). 3. **Option 1: Both \( \lambda \) and \( D \) are doubled**: - New fringe width \( \beta' = \frac{2\lambda \cdot 2D}{d} = \frac{4\lambda D}{d} \) - This is not equal to \( \beta \). Thus, this option is incorrect. 4. **Option 2: Both \( d \) and \( D \) are doubled**: - New fringe width \( \beta' = \frac{\lambda \cdot 2D}{2d} = \frac{\lambda D}{d} \) - This is equal to \( \beta \). Thus, this option is correct. 5. **Option 3: \( d \) is doubled and \( D \) is halved**: - New fringe width \( \beta' = \frac{\lambda \cdot \frac{D}{2}}{2d} = \frac{\lambda D}{4d} \) - This is not equal to \( \beta \). Thus, this option is incorrect. 6. **Option 4: \( \lambda \) is doubled and \( d \) is halved**: - New fringe width \( \beta' = \frac{2\lambda \cdot D}{\frac{d}{2}} = \frac{4\lambda D}{d} \) - This is not equal to \( \beta \). Thus, this option is incorrect. ### Conclusion: The only option that keeps the fringe width the same is **Option 2**, where both \( d \) and \( D \) are doubled.

To solve the problem regarding the fringe width in a Young's double slit experiment, we need to analyze how changes in the parameters affect the fringe width. The formula for fringe width (β) is given by: \[ \beta = \frac{\lambda D}{d} \] where: - \( \beta \) = fringe width ...
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Knowledge Check

  • In a Young's double slit esperiment, the angular width of a fringe formed on a distant screen is 1^(@) . The slit separation is 0.01 mm. The wavelength of the light is

    A
    0.174 nm
    B
    0.174 Ã…
    C
    0.174 `mu m`
    D
    `0.174 xx 10^(-4)m`
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