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If f : R to R defined by f(x) = 1+x^(2)...

If f : `R to R ` defined by `f(x) = 1+x^(2),` then show that f is neither 1-1 nor onto.

Answer

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Knowledge Check

  • Let f: R to R be defined by f(x) = x^(4) , then

    A
    f is one-one but not onto
    B
    f is neither one-one nor onto
    C
    f is one-one and onto
    D
    f may be one-one and onto
  • Let f : R to R be defined by f(x)=x^(4) , then

    A
    1.f is one - one and onto
    B
    2.f may be one - one and onto
    C
    3.f is one - one but not onto
    D
    4.f is neither one - one nor onto
  • If f = R rightarrow R is defined by f(x) = |x| , then,

    A
    `f^(-1)(x) = -x`
    B
    `f^(-1)(x) = (1)/|x|`
    C
    the function `f^(-1)(x)` does not exist
    D
    `f^(-1)(x) =(1)/(x)`
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