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A particle moves along a straight line s...

A particle moves along a straight line such that its displacement at any time t is given by `x =t^3-6t^2 +3t +4` in m. The velocity when acceleration is zero is

A

` 3 ms^-1`

B

` -12 ms^-1`

C

` 42 ms^-1`

D

` -9 ms^-1`

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Knowledge Check

  • If the displacement s at a time t is given by s = sqrt(1-t) , than the velocity is

    A
    directly proportional to displacement
    B
    inversely proportional to displacement
    C
    equal to displacement
    D
    None of these

  • For a particle moving on a straight line it is observed that the distance 's' and time 't' is given by s = 6t -1/2 t^(3) . The maximum velocity during the motion is

    A
    3
    B
    6
    C
    9
    D
    12

  • The distance moved by the particle in time t is given by x=t^(3)-12t^(2)+6t+8 At the instant when its acceleration is zero, the velocity is

    A
    42
    B
    (-42)
    C
    48
    D
    (-48)

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