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To 50 mL of 0.5 M H(2)SO4 75 mL of 0.25 ...

To 50 mL of 0.5 M `H_(2)SO_4` 75 mL of 0.25 M `H_2SO_4` is added. What is the concentration of the final solution if its volume is 125 mL?

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To find the concentration of the final solution after mixing two solutions of sulfuric acid (H₂SO₄), we can follow these steps: ### Step 1: Calculate the number of moles of H₂SO₄ in each solution. 1. **For the first solution (50 mL of 0.5 M H₂SO₄):** - Volume (V₁) = 50 mL = 0.050 L - Molarity (M₁) = 0.5 M - Moles of H₂SO₄ (n₁) = M₁ × V₁ = 0.5 mol/L × 0.050 L = 0.025 moles ...
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100 mL of 0.1 M HCl + 100 mL of 0.2 M H_(2)SO_(4) + 100 mL of 0.1 M HNO_(3) are mixed togther. a. What is the final conecntration of the solution. b. What would be the final concentration of the solution. If the solution is made to 1 L by adding H_(2) O ? c. What would be the final concentration of the solution if 700 mL of H_(2)O is added to the solution?

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Knowledge Check

  • A 50.0 mL solution of 0.150 M HCl. Is mixed with 25.0 mL of 0.400 M HCl What is the HCI concentration in the final solution? (Assume volumes are additive.)

    A
    0.0175
    B
    0.233
    C
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    D
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  • When 50 mL of 0.1M - NaOH and 50 mL of 0.1 M-H_(2)SO_(4) solutions are mixed, the nature of resulting solution is

    A
    Neutral
    B
    Acidic
    C
    Basic
    D
    Amophoteric
  • 100ml of 0.2 M H_(2)SO_(4) is added to 100 ml of 0.2 M NaOH . The resulting solution will be

    A
    Acidic
    B
    Basic
    C
    Neutral
    D
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