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To 50 mL of 0.5 M H(2)SO4 75 mL of 0.25 ...

To 50 mL of 0.5 M `H_(2)SO_4` 75 mL of 0.25 M `H_2SO_4` is added. What is the concentration of the final solution if its volume is 125 mL?

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To find the concentration of the final solution after mixing two solutions of sulfuric acid (H₂SO₄), we can follow these steps: ### Step 1: Calculate the number of moles of H₂SO₄ in each solution. 1. **For the first solution (50 mL of 0.5 M H₂SO₄):** - Volume (V₁) = 50 mL = 0.050 L - Molarity (M₁) = 0.5 M - Moles of H₂SO₄ (n₁) = M₁ × V₁ = 0.5 mol/L × 0.050 L = 0.025 moles ...
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RC MUKHERJEE-ELEMENTARY PROBLEMS BASED ON DEFINITION OF MOLE: THE MOLE CONCEPT -OBJECTIVE PROBLEMS
  1. To 50 mL of 0.5 M H(2)SO4 75 mL of 0.25 M H2SO4 is added. What is the ...

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  2. The density of chlorine relative to air is

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  3. A gaseous nitrogen oxide contains 30.4% of nitrogen, one molecule of w...

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  4. The mass of an oxygen atom is half that of a sulphur atom. Can we deci...

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  5. Density of air is 0.001293 g ml. Its vapour density is

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  6. 5.6 litres of oxygen at NTP is equivalent to

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  7. 22.4 litre of water vapour at NTP, When condensed to water occupies an...

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  8. Which of the following has the highest mass?

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  9. 6.022 xx 10^(22) molecules of N(2) at NTP will occupy a volume of

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  10. How many grams are contained in 1 gram-atom of Na?

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  11. The weight of 350 ml a diatomic gas at 0^(@)C and 2atm pressure is 1 g...

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  12. The number of atoms present in 16 g of oxygen is:

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  13. 1 mole of a compound contains 1 mole of C and 2 moles of O. The molecu...

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  14. The volume of a gas at 0°C and 700 mm pressure is 760 cc. The number o...

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  15. 1 mole of a diatomic element X2 contains 34 and 40 moles of electrons ...

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  16. 2 moles of H atoms at NTP occupy a volume of:

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  17. Number of electrons in 1.8 grams of H(2)O are

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  18. Molecular weight of a gas, 11.2 litres of which at NTP weighs 14 g, is

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  19. The weight of 1 mole of a gas of density 0.1784 g/L at NTP is

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  20. Number of HCl molecules present in 10 mL of 0.1 N HCl solution is

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  21. Number of atoms in 12 g of ""(6)^(12) C is :

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