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The amplitude of (1)/(i) is...

The amplitude of `(1)/(i)` is

A

(a) 0

B

(b) `pi`

C

(c) `(pi)/(2)`

D

(d) `-(pi)/(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the amplitude of \( \frac{1}{i} \), we can follow these steps: ### Step 1: Define the complex number Let \( Z = \frac{1}{i} \). ### Step 2: Multiply by the conjugate To simplify \( Z \), we can multiply the numerator and the denominator by \( i \): \[ Z = \frac{1}{i} \cdot \frac{i}{i} = \frac{i}{i^2} \] ### Step 3: Substitute the value of \( i^2 \) We know that \( i^2 = -1 \). Therefore, \[ Z = \frac{i}{-1} = -i \] ### Step 4: Identify the real and imaginary parts Now, we can express \( Z \) in terms of its real and imaginary parts: \[ Z = 0 - i \] Here, the real part \( a = 0 \) and the imaginary part \( b = -1 \). ### Step 5: Calculate the amplitude The amplitude (or argument) \( \theta \) of a complex number \( Z = a + bi \) is given by: \[ \tan \theta = \frac{b}{a} \] Substituting the values of \( a \) and \( b \): \[ \tan \theta = \frac{-1}{0} \] Since division by zero is undefined, we interpret this as \( \tan \theta \) approaching negative infinity. ### Step 6: Determine the angle The angle \( \theta \) for which \( \tan \theta \) approaches negative infinity is: \[ \theta = -\frac{\pi}{2} \] ### Conclusion Thus, the amplitude of \( \frac{1}{i} \) is: \[ \text{Amplitude} = -\frac{\pi}{2} \] ### Final Answer The correct option is \( \text{D} \, -\frac{\pi}{2} \). ---
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