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In van der Waal's equations (P+a/(V^(2))...

In van der Waal's equations `(P+a/(V^(2)))(V-b)=RT`, what are the dimensions of the constants a and b?

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To find the dimensions of the constants \( a \) and \( b \) in van der Waals' equation \((P + \frac{a}{V^2})(V - b) = RT\), we will analyze the equation step by step. ### Step 1: Understand the Equation The van der Waals equation is given by: \[ (P + \frac{a}{V^2})(V - b) = RT \] Here, \( P \) is pressure, \( V \) is volume, \( R \) is the universal gas constant, and \( T \) is temperature. ...
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Knowledge Check

  • In the Van der Waals equation (P + (a)/(V^(2)))(V-b) = constant, the unit of a is

    A
    dyne/`cm^(5)`
    B
    dyne/`cm^(4)`
    C
    dyne/`cm^(3)`
    D
    dyne/`cm^(2)`

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