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A particle of mass M moves in a circular...

A particle of mass M moves in a circular path if radius r with a constant speed equal to V. Then its centripetal acceleration is

A

`(V^(2))/( r)`

B

`(V^(2))/(r^(2))`

C

`V^(2)r`

D

zero

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • A particle of mass M moves in a circular path of radius r with a constant speed equal to V. Then its centripetal acceleration is

    A
    `(v^(2))/(r)`
    B
    `(v^(2))/(r^(2))`
    C
    `v^(2)r`
    D
    zero

  • A particle of mass M moves in a circular path of radius r with a constant speed equal to V. Then its centripetal acceleration is

    A
    `V^(2)/r`
    B
    `V^(2)/r^(2)`
    C
    `V^(2)r`
    D
    zero

  • A particle of mass m is moving in a circular pat of constant radius r such that its centripetal acceleration a_(c) is varying with time t as a_(c)=k^(2)rt^(2) where k is a constant. The power delivered to the particle by the force acting on it is

    A
    `2pimk^(2)r^(2)`
    B
    `mk^(2)r^(2)t`
    C
    `((mk^(4)r^(2)t^(5)))/3`
    D
    zero

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