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If one of the interior angles of a regul...

If one of the interior angles of a regular polygon is equal to `5//6` times of one of the interior angles of a regular pentagon, then the number of sides of the polygon is:

A

3

B

4

C

6

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step-by-step, we need to find the number of sides of a regular polygon given that one of its interior angles is equal to \( \frac{5}{6} \) times the interior angle of a regular pentagon. ### Step 1: Calculate the interior angle of a regular pentagon. The formula for the interior angle \( A \) of a regular polygon with \( n \) sides is given by: \[ A = \frac{(n-2) \times 180}{n} \] For a pentagon, \( n = 5 \): \[ A = \frac{(5-2) \times 180}{5} = \frac{3 \times 180}{5} = \frac{540}{5} = 108 \text{ degrees} \] ### Step 2: Find the interior angle of the regular polygon. According to the problem, the interior angle \( A_p \) of the regular polygon is: \[ A_p = \frac{5}{6} \times 108 \] Calculating this gives: \[ A_p = \frac{5 \times 108}{6} = \frac{540}{6} = 90 \text{ degrees} \] ### Step 3: Set up the equation for the interior angle of the polygon. Let \( n \) be the number of sides of the regular polygon. We can set up the equation: \[ \frac{(n-2) \times 180}{n} = 90 \] ### Step 4: Solve for \( n \). Multiply both sides by \( n \): \[ (n-2) \times 180 = 90n \] Expanding this gives: \[ 180n - 360 = 90n \] Now, rearranging the equation: \[ 180n - 90n = 360 \] \[ 90n = 360 \] Dividing both sides by 90: \[ n = \frac{360}{90} = 4 \] ### Conclusion The number of sides of the polygon is \( n = 4 \).
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Knowledge Check

  • In one of the interior angles of a regular polygon is equal to 5/6 times of one of the interior angles of a regular pentagon, then the number of sides of the polygon is :

    A
    3
    B
    4
    C
    6
    D
    8
  • If one of the interior angles of a regular polygon is found to be equal to (9/8) times of one of the interior angles of a regular hexagon, then the number of sides of the polygon is

    A
    4
    B
    5
    C
    1
    D
    8
  • If the sum of Interior angles of a regular polygon is equal to two times the sum of exterior angles of that polygon, then the number of sides of that polygon is

    A
    5
    B
    6
    C
    7
    D
    8
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