Match item (A) `NH_(4)Cl`, (B) `NH_(4)OH`, ( C) NaCl, (D) `FeCl_(3)`, (E) `NaHSO_(4)`, (F) NaOH with the correct description given in (i)-(vi) below.
(i) It is a weak base.
(ii) It is a salt of strong acid and a strong base.
(iii) It is formed by direct combination.
(iv) Its aqueous solution has acidic nature.
(v) It gives pink colour with phenolphthalein.
(vi) It is an acid salt.

Answer

To solve the matching question, we need to analyze each item and description carefully. Here’s the step-by-step solution:

### Step 1: Analyze Each Item
1. **(A) NH₄Cl (Ammonium Chloride)**: This is a salt formed from a weak base (NH₄OH) and a strong acid (HCl).
2. **(B) NH₄OH (Ammonium Hydroxide)**: This is a weak base.
3. **(C) NaCl (Sodium Chloride)**: This is a salt formed from a strong base (NaOH) and a strong acid (HCl).
4. **(D) FeCl₃ (Iron(III) Chloride)**: This is formed by the direct combination of iron and chlorine.
5. **(E) NaHSO₄ (Sodium Hydrogen Sulfate)**: This is an acid salt.
6. **(F) NaOH (Sodium Hydroxide)**: This is a strong base.

### Step 2: Match with Descriptions
- **(i) It is a weak base.**
- **Match with (B) NH₄OH.**

- **(ii) It is a salt of strong acid and a strong base.**
- **Match with (C) NaCl.**

- **(iii) It is formed by direct combination.**
- **Match with (D) FeCl₃.**

- **(iv) Its aqueous solution has acidic nature.**
- **Match with (A) NH₄Cl.**

- **(v) It gives pink colour with phenolphthalein.**
- **Match with (F) NaOH.**

- **(vi) It is an acid salt.**
- **Match with (E) NaHSO₄.**

### Final Matches
- (A) NH₄Cl → (iv) Its aqueous solution has acidic nature.
- (B) NH₄OH → (i) It is a weak base.
- (C) NaCl → (ii) It is a salt of strong acid and a strong base.
- (D) FeCl₃ → (iii) It is formed by direct combination.
- (E) NaHSO₄ → (vi) It is an acid salt.
- (F) NaOH → (v) It gives pink colour with phenolphthalein.