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If sin A = n sin B then (n-1)/(n+1) tan ...

If `sin A = n sin B` then `(n-1)/(n+1)` tan `(A+B)/(2)` is equal to

A

`sin((A-B)/(2))`

B

`tan((A-B)/(2))`

C

`cot((A-B)/(2))`

D

`tan((A+B)/(2))`

Text Solution

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The correct Answer is:
A, B
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