Equivalent mass of `C_(2)O_(4)^(2-)` ion in the reaction,
`C_(2)O_(4)^(2-)to2CO_(2)+2e^(-)`, is

Options

A. 11
B. 22
C. 44
D. 88

Answer

To find the equivalent mass of the \( C_2O_4^{2-} \) ion in the reaction

\[ C_2O_4^{2-} \rightarrow 2CO_2 + 2e^- \]

we will follow these steps:

### Step 1: Determine the n-factor
The n-factor is defined as the total number of electrons lost or gained in the reaction. In this case, we can see that \( C_2O_4^{2-} \) is losing 2 electrons to form \( 2CO_2 \). Thus, the n-factor for this reaction is 2.

### Step 2: Calculate the molecular mass of \( C_2O_4^{2-} \)
To find the molecular mass, we need to sum the atomic masses of all the atoms in the ion:
- Carbon (C) has an atomic mass of approximately 12 g/mol.
- Oxygen (O) has an atomic mass of approximately 16 g/mol.

The molecular mass of \( C_2O_4^{2-} \) is calculated as follows:

\[ \text{Molecular mass} = 2 \times (12) + 4 \times (16) \]
\[ = 24 + 64 \]
\[ = 88 \text{ g/mol} \]

### Step 3: Calculate the equivalent mass
The equivalent mass is calculated using the formula:

\[ \text{Equivalent mass} = \frac{\text{Molecular mass}}{n \text{-factor}} \]

Substituting the values we found:

\[ \text{Equivalent mass} = \frac{88 \text{ g/mol}}{2} = 44 \text{ g/equiv} \]

### Conclusion
Thus, the equivalent mass of the \( C_2O_4^{2-} \) ion is **44 g/equiv**.

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