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MnO(4)^(-) is a good oxidising agent in ...

`MnO_(4)^(-)` is a good oxidising agent in different mediums changing to
`MnO_(4)^(-)toMn^(2+)`
`toMnO_(4)^(2-)`
`toMnO_(2)`
`toMn_(2)O_(3)`
Changes in oxidation number respectively are

A

1,3,4,5

B

5,4,3,2

C

5,1,3,4

D

2,6,4,3

Text Solution

AI Generated Solution

The correct Answer is:
To determine the changes in oxidation numbers for the conversions of \( \text{MnO}_4^{-} \) to \( \text{Mn}^{2+} \), \( \text{MnO}_4^{2-} \), \( \text{MnO}_2 \), and \( \text{Mn}_2\text{O}_3 \), we will follow these steps: ### Step 1: Determine the oxidation state of manganese in \( \text{MnO}_4^{-} \) Let the oxidation state of manganese be \( x \). Using the formula for oxidation states: \[ x + 4(-2) = -1 \] \[ x - 8 = -1 \] \[ x = +7 \] ### Step 2: Calculate the change in oxidation state from \( \text{MnO}_4^{-} \) to \( \text{Mn}^{2+} \) The oxidation state of manganese in \( \text{Mn}^{2+} \) is \( +2 \). Change in oxidation state: \[ +7 \text{ to } +2 \quad \Rightarrow \quad 7 - 2 = 5 \] ### Step 3: Determine the oxidation state of manganese in \( \text{MnO}_4^{2-} \) Let the oxidation state of manganese be \( x \). Using the formula for oxidation states: \[ x + 4(-2) = -2 \] \[ x - 8 = -2 \] \[ x = +6 \] ### Step 4: Calculate the change in oxidation state from \( \text{MnO}_4^{2-} \) to \( \text{Mn}^{2+} \) Change in oxidation state: \[ +6 \text{ to } +2 \quad \Rightarrow \quad 6 - 2 = 4 \] ### Step 5: Determine the oxidation state of manganese in \( \text{MnO}_2 \) Let the oxidation state of manganese be \( x \). Using the formula for oxidation states: \[ x + 2(-2) = 0 \] \[ x - 4 = 0 \] \[ x = +4 \] ### Step 6: Calculate the change in oxidation state from \( \text{MnO}_2 \) to \( \text{Mn}^{2+} \) Change in oxidation state: \[ +4 \text{ to } +2 \quad \Rightarrow \quad 4 - 2 = 2 \] ### Step 7: Determine the oxidation state of manganese in \( \text{Mn}_2\text{O}_3 \) Let the oxidation state of manganese be \( x \). Using the formula for oxidation states: \[ 2x + 3(-2) = 0 \] \[ 2x - 6 = 0 \] \[ 2x = 6 \quad \Rightarrow \quad x = +3 \] ### Step 8: Calculate the change in oxidation state from \( \text{Mn}_2\text{O}_3 \) to \( \text{Mn}^{2+} \) Change in oxidation state: \[ +3 \text{ to } +2 \quad \Rightarrow \quad 3 - 2 = 1 \] ### Summary of Changes in Oxidation Number 1. From \( \text{MnO}_4^{-} \) to \( \text{Mn}^{2+} \): Change = 5 2. From \( \text{MnO}_4^{2-} \) to \( \text{Mn}^{2+} \): Change = 4 3. From \( \text{MnO}_2 \) to \( \text{Mn}^{2+} \): Change = 2 4. From \( \text{Mn}_2\text{O}_3 \) to \( \text{Mn}^{2+} \): Change = 1 Thus, the changes in oxidation numbers respectively are: **5, 4, 2, 1**. ### Final Answer The correct option is **5, 4, 2, 1**.
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