A flywheel starts rotating from rest when a torque is applied on it, with a uniform angular acceleration of `5 "rad"//s^(2)`. What is the angular displacement of the flywheel in the 5th Second ?

Explanation

To find the angular displacement of the flywheel in the 5th second, we can use the formula for angular displacement during the nth second of motion under uniform angular acceleration. The formula is:

\[ \theta_n = \omega_0 + \frac{\alpha}{2} \cdot (2n - 1) \]

Where:
- \(\theta_n\) = angular displacement during the nth second
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