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A ray of light incident at an angle of i...

A ray of light incident at an angle of incidence `48^(@)` on a prism of refracting angle `60^(@)` suffers minimum deviation. Calculate the angle of minimum deviation.

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To solve the problem of finding the angle of minimum deviation for a ray of light incident on a prism, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the given values**: - Angle of incidence (i) = 48° - Angle of the prism (A) = 60° 2. **Recall the formula for deviation**: - The formula for the angle of deviation (Δ) is given by: \[ \Delta = i + e - A \] where \( e \) is the angle of emergence. 3. **Apply the condition for minimum deviation**: - For minimum deviation, the angle of emergence (e) is equal to the angle of incidence (i). Therefore: \[ e = i = 48° \] 4. **Substitute the values into the deviation formula**: - Now substitute \( i \), \( e \), and \( A \) into the deviation formula: \[ \Delta_{min} = i + e - A \] - This becomes: \[ \Delta_{min} = 48° + 48° - 60° \] 5. **Calculate the minimum deviation**: - Perform the arithmetic: \[ \Delta_{min} = 96° - 60° = 36° \] 6. **Final Result**: - Therefore, the angle of minimum deviation is: \[ \Delta_{min} = 36° \]
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