Home
Class 11
CHEMISTRY
The number of atoms in 0.004 g of magnes...

The number of atoms in 0.004 g of magnesium is close to

A

24

B

`2 xx 10^(20)`

C

`10^(20)`

D

`6.02 xx 10^(23)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of atoms in 0.004 g of magnesium, we will follow these steps: ### Step 1: Identify the given data - Given mass of magnesium (Mg) = 0.004 g - Molar mass of magnesium = 24 g/mol ### Step 2: Calculate the number of moles of magnesium Using the formula for moles: \[ \text{Moles} = \frac{\text{Given mass (g)}}{\text{Molar mass (g/mol)}} \] Substituting the values: \[ \text{Moles of Mg} = \frac{0.004 \text{ g}}{24 \text{ g/mol}} = 1.6667 \times 10^{-4} \text{ moles} \] ### Step 3: Use Avogadro's number to find the number of atoms Avogadro's number (N_A) is \(6.022 \times 10^{23}\) atoms/mol. The formula to find the number of atoms is: \[ \text{Number of atoms} = \text{Moles} \times N_A \] Substituting the values: \[ \text{Number of Mg atoms} = 1.6667 \times 10^{-4} \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mol} \] ### Step 4: Perform the calculation Calculating the number of atoms: \[ \text{Number of Mg atoms} \approx 1.0 \times 10^{20} \text{ atoms} \] ### Conclusion Thus, the number of atoms in 0.004 g of magnesium is approximately \(1.0 \times 10^{20}\) atoms. ---

To find the number of atoms in 0.004 g of magnesium, we will follow these steps: ### Step 1: Identify the given data - Given mass of magnesium (Mg) = 0.004 g - Molar mass of magnesium = 24 g/mol ### Step 2: Calculate the number of moles of magnesium Using the formula for moles: ...
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    ICSE|Exercise TRUE OR FALSE TYPE QUESTIONS |10 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    ICSE|Exercise FILL IN THE BLANKS TYPE QUESTIONS |10 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    ICSE|Exercise ESSAY LONG ANSWER TYPE QUESTIONS |15 Videos
  • SELF ASSESSMENT PAPER 2

    ICSE|Exercise Questions|62 Videos
  • SOME P-BLOCK ELEMENTS

    ICSE|Exercise NCERT TEXTBOOK EXERCISES (With Hints and Solutions)|63 Videos

Similar Questions

Explore conceptually related problems

Find number of atoms in 46g of Na?

The number of atoms in 100 g of an fcc crystal with density = 10.0g cm^(-3) and cell edge equal to 200 pm is equal to

The number of atoms presents in 20 g of calcium will equal to the number of atoms presents in

Calculate number of atoms in 1.8 g of water.

Calculate the mass of sodium which contains the same number of atoms as are present in 10 g of magnesium.

The number of atoms present in a 0.635 g of Cu piece will be :

The number of atoms present in 1 g of hydrogen is the same as that in 1 g of oxygen.

The number of atoms in 20 g of SO_(3) is approximately

The number of atoms in 20 g of SO_(3) is approximately

Calculate number of atoms in 1.2 g of carbon.

ICSE-SOME BASIC CONCEPTS OF CHEMISTRY -OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS (CHOOSE THE CORRECT OPTION IN THE FOLLOWING QUESTIONS)
  1. The number of grams of H2SO4 required to dissolve 5 g of CaCO(3) is:

    Text Solution

    |

  2. The mass of a mole of electrons is: 0.008 g 0.184 g 0.55 mg 1.673

    Text Solution

    |

  3. The number of atoms in 0.004 g of magnesium is close to

    Text Solution

    |

  4. Two samples of lead oxide were separately reduced to metallic lead by ...

    Text Solution

    |

  5. Chemical equation is balanced according to the law of multiple proport...

    Text Solution

    |

  6. The number of water molecules in one litre of water is:

    Text Solution

    |

  7. The total number of electrons present in 18 mL of water (density of wa...

    Text Solution

    |

  8. 18 g of water contain:

    Text Solution

    |

  9. An oxide of metal M has 40% by mass of oxygen. Metal M has relative at...

    Text Solution

    |

  10. The mass of an atom of oxygen is:

    Text Solution

    |

  11. 1 mole of methane (CH4) contains

    Text Solution

    |

  12. Two elements A (At. wt. 75) and B (At. wt. 16) combine to yield a comp...

    Text Solution

    |

  13. The equivalent mass of MnSO4 is half of its molecular mass when it is ...

    Text Solution

    |

  14. 5 mL of N HCI, 20 mL of N/2 H2SO4 and 30 mL of N/3 HNO3 are mixed tog...

    Text Solution

    |

  15. 100 g of a solution of hydrochloric acid (sp.gr. 1.18) contains 36.5 g...

    Text Solution

    |

  16. A sample of Na2CO3H2O weighing 0.62 g is added to 100 mL of 0.1 N H2SO...

    Text Solution

    |

  17. 2.76 g of Ag2CO3 on being heated yields a residue weighing

    Text Solution

    |

  18. The number of moles of KMnO4 that are needed to react completely with ...

    Text Solution

    |

  19. Normality of a '30 volume H2O2' solution is:

    Text Solution

    |

  20. Equal volumes of 1M KMnO4 and 1M K2Cr2O7 solution are allowed to oxidi...

    Text Solution

    |