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The number of atoms present in 1 g of hy...

The number of atoms present in 1 g of hydrogen is the same as that in 1 g of oxygen.

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To determine whether the number of atoms present in 1 g of hydrogen is the same as that in 1 g of oxygen, we will follow these steps: ### Step 1: Understand the concept of moles The number of moles (n) can be calculated using the formula: \[ n = \frac{\text{mass}}{\text{molar mass}} \] ### Step 2: Calculate the number of moles of oxygen (O2) 1. The molar mass of oxygen (O2) is 32 g/mol (since each oxygen atom has a molar mass of 16 g/mol, and there are two atoms in O2). 2. For 1 g of O2: \[ n_{\text{O2}} = \frac{1 \text{ g}}{32 \text{ g/mol}} = \frac{1}{32} \text{ mol} \] ### Step 3: Calculate the number of atoms in 1 g of oxygen 1. To find the number of oxygen atoms, we multiply the number of moles by Avogadro's number (approximately \(6.022 \times 10^{23}\) atoms/mol): \[ \text{Number of atoms in O2} = n_{\text{O2}} \times N_A = \frac{1}{32} \text{ mol} \times 6.022 \times 10^{23} \text{ atoms/mol} \approx 1.87 \times 10^{22} \text{ atoms} \] ### Step 4: Calculate the number of moles of hydrogen (H2) 1. The molar mass of hydrogen (H2) is 2 g/mol (since each hydrogen atom has a molar mass of 1 g/mol, and there are two atoms in H2). 2. For 1 g of H2: \[ n_{\text{H2}} = \frac{1 \text{ g}}{2 \text{ g/mol}} = \frac{1}{2} \text{ mol} \] ### Step 5: Calculate the number of atoms in 1 g of hydrogen 1. To find the number of hydrogen atoms, we multiply the number of moles by Avogadro's number: \[ \text{Number of atoms in H2} = n_{\text{H2}} \times N_A = \frac{1}{2} \text{ mol} \times 6.022 \times 10^{23} \text{ atoms/mol} \approx 3.01 \times 10^{23} \text{ atoms} \] ### Step 6: Compare the number of atoms 1. From the calculations: - Number of atoms in 1 g of O2: \( \approx 1.87 \times 10^{22} \text{ atoms} \) - Number of atoms in 1 g of H2: \( \approx 3.01 \times 10^{23} \text{ atoms} \) ### Conclusion Since \(1.87 \times 10^{22} \neq 3.01 \times 10^{23}\), the statement that the number of atoms present in 1 g of hydrogen is the same as that in 1 g of oxygen is **false**. ---
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Knowledge Check

  • Total number of atoms present in 34 g of NH_3 is

    A
    `4xx10^23`
    B
    `4.8xx10^21`
    C
    `2xx10^23`
    D
    `48xx10^23`
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