Home
Class 10
MATHS
In a regular pentagon ABCDE inscribed i...

In a regular pentagon ABCDE inscribed in a circle . Find the ratio between angle ADE and angle ADC.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio between angle ADE and angle ADC in a regular pentagon ABCDE inscribed in a circle, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Pentagon**: - We have a regular pentagon ABCDE inscribed in a circle. In a regular pentagon, all sides and angles are equal. 2. **Drawing the Diagram**: - Draw a circle and inscribe the pentagon ABCDE. Mark the center of the circle as O. 3. **Calculating Central Angles**: - The total angle around point O (the center of the circle) is 360 degrees. Since the pentagon has 5 equal angles at the center, each central angle (like angle AOE) can be calculated as: \[ \text{Angle AOE} = \frac{360^\circ}{5} = 72^\circ \] 4. **Finding Angle ADE**: - Angle ADE is subtended by arc AE at the circumference. The angle subtended at the circumference is half of the angle subtended at the center. Therefore: \[ \text{Angle ADE} = \frac{1}{2} \times \text{Angle AOE} = \frac{1}{2} \times 72^\circ = 36^\circ \] 5. **Finding Angle ADC**: - Angle ADC is the sum of angles ADB and BDC. Since both angles are subtended by the arcs AB and BC respectively, and each subtended angle at the circumference is also 36 degrees: \[ \text{Angle ADB} = 36^\circ \quad \text{and} \quad \text{Angle BDC} = 36^\circ \] - Thus, we can calculate angle ADC as: \[ \text{Angle ADC} = \text{Angle ADB} + \text{Angle BDC} = 36^\circ + 36^\circ = 72^\circ \] 6. **Finding the Ratio**: - Now, we can find the ratio of angle ADE to angle ADC: \[ \text{Ratio} = \frac{\text{Angle ADE}}{\text{Angle ADC}} = \frac{36^\circ}{72^\circ} = \frac{1}{2} \] 7. **Final Answer**: - Therefore, the ratio of angle ADE to angle ADC is: \[ \text{Angle ADE : Angle ADC} = 1 : 2 \]
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CIRCLES

    ICSE|Exercise EXERCISE 17( C ) |28 Videos
  • CIRCLES

    ICSE|Exercise EXERCISE 17(A) |58 Videos
  • CHAPTERWISE REVISION EXERCISE

    ICSE|Exercise CHAPTERWISE REVISION EXERCISE (PROBABILITY)|16 Videos
  • CONSTRUCTIONS (CIRCLES)

    ICSE|Exercise EXERCISE|39 Videos

Similar Questions

Explore conceptually related problems

If a square is inscribed in a circle, find the ratio of the areas of the circle and the square.

If a square is inscribed in a circle, find the ratio of the areas of the circle and the square.

In the given figure, ABCDE is a pentagone inscribed in a circle such that AC is a diameter and side BC//AE. If angleBAC=50^(@) , find angleBCE ,

In the given figure, AB is a side of a regular pentagon and BC is the side of a regular hexagon. Find (i) angle AOB (ii) angle OBC

In a regular pentagon ABCDE, draw a diagonal BE and then find the measure of : (i) angleBAE (ii) angleABE (iii) angleBED

In the given figure, ABCDE is a pentagone inscribed in a circle such that AC is a diameter and side BC//AE. If angleBAC =50^(@) , find giving reasons : (i) angleACB (ii) angleEDC (iii) angleBEC Hence prove that BE is also a diameter.

If the area of the circle is A_1 and the area of the regular pentagon inscribed in the circle is A_2, then find the ratio (A_1)/(A_2)dot

If the area of the circle is A_1 and the area of the regular pentagon inscribed in the circle is A_2, then find the ratio (A_1)/(A_2)dot

In a pentagon ABCDE, AB is parallel to ED and angle B= 140^(@) . Find the angles C and D, if angleC: angleD= 5: 6

A rectangle ABCD is inscribed in a circle. Let PQ be the diameter of the circle parallel the side AB. If /_BPC = 30^@ , then the ratio of the area of rectangle to the area of circle is