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A solid sphere of radius 15 cm is melted...

A solid sphere of radius 15 cm is melted and recast into solid right circular cones of radius 2.5 cm and height 8 cm. Calculate the number of cones recast.

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To solve the problem of finding the number of cones recast from a melted solid sphere, we will follow these steps: ### Step 1: Calculate the Volume of the Sphere The formula for the volume \( V_s \) of a sphere is given by: \[ V_s = \frac{4}{3} \pi R^3 \] where \( R \) is the radius of the sphere. Given: - Radius of the sphere \( R = 15 \, \text{cm} \) Substituting the value into the formula: \[ V_s = \frac{4}{3} \pi (15)^3 \] Calculating \( 15^3 \): \[ 15^3 = 3375 \] Thus, \[ V_s = \frac{4}{3} \pi (3375) = 4500 \pi \, \text{cm}^3 \] ### Step 2: Calculate the Volume of One Cone The formula for the volume \( V_c \) of a cone is given by: \[ V_c = \frac{1}{3} \pi r^2 h \] where \( r \) is the radius and \( h \) is the height of the cone. Given: - Radius of the cone \( r = 2.5 \, \text{cm} \) - Height of the cone \( h = 8 \, \text{cm} \) Substituting the values into the formula: \[ V_c = \frac{1}{3} \pi (2.5)^2 (8) \] Calculating \( (2.5)^2 \): \[ (2.5)^2 = 6.25 \] Thus, \[ V_c = \frac{1}{3} \pi (6.25)(8) = \frac{1}{3} \pi (50) = \frac{50}{3} \pi \, \text{cm}^3 \] ### Step 3: Calculate the Number of Cones To find the number of cones \( n \) recast from the melted sphere, we use the relationship: \[ n = \frac{V_s}{V_c} \] Substituting the volumes we calculated: \[ n = \frac{4500 \pi}{\frac{50}{3} \pi} \] The \( \pi \) cancels out: \[ n = \frac{4500}{\frac{50}{3}} = 4500 \times \frac{3}{50} = \frac{13500}{50} = 270 \] ### Final Answer The number of cones recast is \( \boxed{270} \). ---
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