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A cylindrical container with diameter of base 42 cm contains sufficient water to submerge a rectangular solid of iron with dimensions `22 cm xx 14 cm xx 10.5 cm.` Find the rise in level of the water when the solid is submerged.

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To solve the problem of finding the rise in water level when a rectangular solid is submerged in a cylindrical container, we can follow these steps: ### Step 1: Understand the dimensions of the cylindrical container and the rectangular solid - The diameter of the cylindrical container is given as 42 cm. - The dimensions of the rectangular solid are given as: - Length (l) = 22 cm - Breadth (b) = 14 cm - Height (h) = 10.5 cm ### Step 2: Calculate the radius of the cylindrical container - The radius (r) of the cylindrical container can be calculated using the formula: \[ r = \frac{\text{Diameter}}{2} = \frac{42 \text{ cm}}{2} = 21 \text{ cm} \] ### Step 3: Calculate the volume of the rectangular solid - The volume (V) of the rectangular solid can be calculated using the formula: \[ V = l \times b \times h \] - Substituting the values: \[ V = 22 \text{ cm} \times 14 \text{ cm} \times 10.5 \text{ cm} \] - Calculating this: \[ V = 22 \times 14 = 308 \text{ cm}^2 \] \[ V = 308 \times 10.5 = 3234 \text{ cm}^3 \] ### Step 4: Set up the equation for the rise in water level - The volume of water displaced by the submerged rectangular solid is equal to the volume of the solid. - The volume of water displaced can also be expressed in terms of the rise in water level (h) in the cylindrical container: \[ \text{Volume of water displaced} = \pi r^2 h \] - Therefore, we can set up the equation: \[ \pi r^2 h = 3234 \text{ cm}^3 \] ### Step 5: Substitute the radius and solve for h - Substitute \( r = 21 \text{ cm} \) into the equation: \[ \pi (21)^2 h = 3234 \] - Calculate \( \pi (21)^2 \): \[ \pi (21)^2 = \pi \times 441 \approx \frac{22}{7} \times 441 \] \[ \approx 1386 \text{ cm}^2 \] - Now substitute this value back into the equation: \[ 1386 h = 3234 \] - Solve for h: \[ h = \frac{3234}{1386} \approx 2.33 \text{ cm} \] ### Final Answer The rise in the level of the water when the solid is submerged is approximately **2.33 cm**. ---
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ICSE-CYLINDER, CONE AND SPHERE -EXERCISE 20 (F)
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