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The equation of the diirectrix of the pa...

The equation of the diirectrix of the parabola is `3x+2y+1-0`. The focus is `(2,1)`. Find the equation of the parabola.

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To find the equation of the parabola given the directrix \(3x + 2y + 1 = 0\) and the focus \((2, 1)\), we can follow these steps: ### Step 1: Identify the focus and directrix The focus of the parabola is given as \(F(2, 1)\) and the equation of the directrix is \(3x + 2y + 1 = 0\). ### Step 2: Set up the distance formula Let \(P(x, y)\) be a point on the parabola. The distance from point \(P\) to the focus \(F(2, 1)\) is given by: \[ d_F = \sqrt{(x - 2)^2 + (y - 1)^2} \] ### Step 3: Find the distance from point \(P\) to the directrix The distance from point \(P(x, y)\) to the directrix \(3x + 2y + 1 = 0\) can be calculated using the formula for the distance from a point to a line: \[ d_D = \frac{|3x + 2y + 1|}{\sqrt{3^2 + 2^2}} = \frac{|3x + 2y + 1|}{\sqrt{13}} \] ### Step 4: Set the distances equal For a parabola, the distance from the point \(P\) to the focus equals the distance from \(P\) to the directrix. Therefore, we have: \[ \sqrt{(x - 2)^2 + (y - 1)^2} = \frac{|3x + 2y + 1|}{\sqrt{13}} \] ### Step 5: Square both sides To eliminate the square root, we square both sides: \[ (x - 2)^2 + (y - 1)^2 = \frac{(3x + 2y + 1)^2}{13} \] ### Step 6: Multiply through by 13 Multiplying both sides by 13 gives: \[ 13((x - 2)^2 + (y - 1)^2) = (3x + 2y + 1)^2 \] ### Step 7: Expand both sides Expanding the left side: \[ 13((x - 2)^2 + (y - 1)^2) = 13((x^2 - 4x + 4) + (y^2 - 2y + 1)) = 13x^2 - 52x + 52 + 13y^2 - 26y + 13 \] This simplifies to: \[ 13x^2 + 13y^2 - 52x - 26y + 65 \] Expanding the right side: \[ (3x + 2y + 1)^2 = 9x^2 + 4y^2 + 1 + 12xy + 6x + 4y \] ### Step 8: Set the equation to zero Now we set the equation: \[ 13x^2 + 13y^2 - 52x - 26y + 65 = 9x^2 + 4y^2 + 1 + 12xy + 6x + 4y \] Rearranging gives: \[ (13x^2 - 9x^2) + (13y^2 - 4y^2) - (52x - 6x) - (26y - 4y) + (65 - 1) - 12xy = 0 \] This simplifies to: \[ 4x^2 + 9y^2 - 12xy - 58x - 30y + 64 = 0 \] ### Final Equation of the Parabola Thus, the equation of the parabola is: \[ 4x^2 + 9y^2 - 12xy - 58x - 30y + 64 = 0 \] ---
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