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If x(hat(i) + hat(j) + hat(k)) is a unit...

If `x(hat(i) + hat(j) + hat(k))` is a unit vector then x equals ?

A

`(1)/(sqrt(3))`

B

`pm sqrt(3)`

C

`sqrt(3)`

D

`pm (1)/(sqrt(3))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( x \) such that the vector \( x(\hat{i} + \hat{j} + \hat{k}) \) is a unit vector. ### Step-by-Step Solution: 1. **Define the Vector**: Let \( \mathbf{a} = x(\hat{i} + \hat{j} + \hat{k}) \). This can be rewritten as: \[ \mathbf{a} = x\hat{i} + x\hat{j} + x\hat{k} \] 2. **Magnitude of the Vector**: The magnitude of vector \( \mathbf{a} \) is given by: \[ |\mathbf{a}| = \sqrt{(x)^2 + (x)^2 + (x)^2} \] This simplifies to: \[ |\mathbf{a}| = \sqrt{3x^2} \] 3. **Set the Magnitude to 1**: Since \( \mathbf{a} \) is a unit vector, we have: \[ |\mathbf{a}| = 1 \] Therefore, we set up the equation: \[ \sqrt{3x^2} = 1 \] 4. **Square Both Sides**: To eliminate the square root, we square both sides: \[ 3x^2 = 1 \] 5. **Solve for \( x^2 \)**: Dividing both sides by 3 gives: \[ x^2 = \frac{1}{3} \] 6. **Find \( x \)**: Taking the square root of both sides, we find: \[ x = \pm \sqrt{\frac{1}{3}} = \pm \frac{1}{\sqrt{3}} \] ### Final Answer: Thus, the value of \( x \) is: \[ x = \pm \frac{1}{\sqrt{3}} \]
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Knowledge Check

  • If the vectors hat(i) - 2x hat(j) + 3 y hat(k) and hat(i) +2x hat(j) - y hat(k) are perpendicular, then the locus of (x,y) is

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    a circle
    B
    on ellipse
    C
    a hyperbola
    D
    none of these
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