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If a girl is wearing a pointed heel whic...

If a girl is wearing a pointed heel which has an area of cross section `2 "cm"^2`, and if her mass is 650 N, find out the pressure exerted by her on the floor (remember to calculate for both legs)

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To solve the problem of finding the pressure exerted by a girl wearing pointed heels on the floor, we will follow these steps: ### Step 1: Understand the formula for pressure Pressure (P) is defined as the force (F) applied per unit area (A). The formula can be written as: \[ P = \frac{F}{A} \] ### Step 2: Identify the force The force exerted by the girl on the floor is equal to her weight, which is given as: \[ F = 650 \, \text{N} \] ### Step 3: Determine the area of one heel The area of cross-section of one pointed heel is given as: \[ A_1 = 2 \, \text{cm}^2 \] To convert this to square meters (since pressure is typically measured in pascals, which uses square meters), we use the conversion factor \( 1 \, \text{cm}^2 = 0.0001 \, \text{m}^2 \): \[ A_1 = 2 \, \text{cm}^2 = 2 \times 0.0001 \, \text{m}^2 = 0.0002 \, \text{m}^2 \] ### Step 4: Calculate the total area for both heels Since the girl is using both heels, the total area (A) is: \[ A = 2 \times A_1 = 2 \times 0.0002 \, \text{m}^2 = 0.0004 \, \text{m}^2 \] ### Step 5: Substitute values into the pressure formula Now we substitute the values of force and total area into the pressure formula: \[ P = \frac{F}{A} = \frac{650 \, \text{N}}{0.0004 \, \text{m}^2} \] ### Step 6: Calculate the pressure Now, we perform the division: \[ P = \frac{650}{0.0004} = 1625000 \, \text{Pascals} \] ### Step 7: Convert to kilopascals To express the pressure in kilopascals (kPa), we divide by 1000: \[ P = 1625000 \, \text{Pascals} = 1625 \, \text{kPa} \] ### Final Answer The pressure exerted by the girl on the floor is: \[ P = 1625 \, \text{kPa} \] ---
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