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Niobium crystallizes in body centred cub...

Niobium crystallizes in body centred cubic structure. If its density is 8.55 g `cm^(-3)`, calculate the atomic radius of niobium. (Atomic mass of Nb = 93u , `N_A = 6.02 xx 10^(23) mol^(-1)`)

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To calculate the atomic radius of niobium (Nb) which crystallizes in a body-centered cubic (BCC) structure, we can follow these steps: ### Step 1: Understand the given data - Density of niobium (ρ) = 8.55 g/cm³ - Atomic mass of niobium (M) = 93 g/mol - Avogadro's number (N_A) = 6.02 x 10²³ mol⁻¹ - The number of atoms per unit cell (Z) in BCC = 2 ...
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Niobium crystallizes in body-centred cubic structure. If the density is 8.55 g cm^(-3) , calculate the atomic radius of niobium using its atomic mass 93 u .

Niobium crystallizes in body-centred cubic structure. If the density is 8.55 g cm^(-3) , calculate the atomic radius of niobium using its atomic mass 93 u .

Knowledge Check

  • The number of atoms in 0.1 mole of a triatomic gas is (N_(A) = 6.02 xx 10^(23) "mol"^(-1))

    A
    `6.026 xx 10^(22)`
    B
    `1.806 xx 10^(23)`
    C
    `3.600 xx 10^(23)`
    D
    `1.800 xx 10^(22)`

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