Increasing order of boiling points is:
1) `H_2O gt H_2S gt H_2Se gt H_2Te`
2) `H_2O gt H_2Te gt H_2Se gt H_2S`
3) `H_2O gt H_2Se gt H_2Te gt H_2S`
4) `H_2O gt H_2S gt H_2 Te gt H_2Se`

Options

A. `H_2O gt H_2S gt H_2Se gt H_2Te`
B. `H_2O gt H_2Te gt H_2Se gt H_2S`
C. `H_2O gt H_2Se gt H_2Te gt H_2S`
D. `H_2O gt H_2S gt H_2 Te gt H_2Se`

Answer

To determine the increasing order of boiling points for the compounds \( H_2O, H_2S, H_2Se, \) and \( H_2Te \), we need to analyze the factors that influence boiling points, particularly for hydrides of group 16 elements.

### Step-by-Step Solution:

1. **Identify the Compounds**: We have four compounds to analyze:
- \( H_2O \) (water)
- \( H_2S \) (hydrogen sulfide)
- \( H_2Se \) (hydrogen selenide)
- \( H_2Te \) (hydrogen telluride)

2. **Understand the Role of Hydrogen Bonding**:
- \( H_2O \) exhibits strong hydrogen bonding due to the high electronegativity of oxygen. This results in a significantly higher boiling point compared to the other hydrides in this group.

3. **Consider Van der Waals Forces**:
- For \( H_2S, H_2Se, \) and \( H_2Te \), the primary intermolecular forces are Van der Waals forces. These forces increase with molecular weight. Therefore, as we move down the group from sulfur to tellurium, the boiling points will increase due to the increasing strength of Van der Waals forces.

4. **Rank the Boiling Points**:
- \( H_2O \) has the highest boiling point due to hydrogen bonding.
- \( H_2S \) has a lower boiling point than \( H_2Se \) and \( H_2Te \) because it has weaker Van der Waals forces.
- \( H_2Se \) has a higher boiling point than \( H_2S \) but lower than \( H_2Te \).
- \( H_2Te \) has the highest boiling point among \( H_2S, H_2Se, \) and \( H_2Te \) due to its larger molecular size and mass.

5. **Final Order**: Thus, the increasing order of boiling points is:
\[ H_2S < H_2Se < H_2Te < H_2O \]

6. **Select the Correct Option**: From the options provided, the correct increasing order of boiling points is:
- **Option 2**: \( H_2O > H_2Te > H_2Se > H_2S \)

### Summary:
The increasing order of boiling points is:
\[ H_2S < H_2Se < H_2Te < H_2O \]
The correct answer is **Option 2**: \( H_2O > H_2Te > H_2Se > H_2S \).