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[Ti(H2O)6]^(3+) is coloured while [Sc(H2...

`[Ti(H_2O)_6]^(3+)` is coloured while `[Sc(H_2O)_6]^(3+)` is colourless . Explain.

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These questions consist of two statements each, printed as Assertion and Reason. While answering these questions you are required to choose any one of the following four responses: Assertion: [Ti(H_2O)_6]^(3+) is coloured while [Sc(H_2O)_6]^(3+) is colourless. Reason: d-d transition is not possible in [Sc(H_2O)_6]^(3+) .

Assertion: [Ti(H_(2)O)_(6)]^(4+) is coloured while [Sc(H_(2)O)_(6)]^(3+) is colourless. Reason: d-d transition is not possible in [Sc(H_(2)O)_(6)]^(3+) .

Knowledge Check

  • CuSO_(4).5H_(2)O is blue in colour while CuSO_(4) is colourless. Why ?

    A
    presence of strong field ligand in `CuSO_(4) * 5H_(2)O`
    B
    absence of water (ligand) , `d-d` transitions are not possible in `CuSO_(4)`
    C
    anhydrous `CuSO_(4)` undergoes d-d transitions due to crystal field splitting
    D
    colour is lost due to loss of unpaired electrons .

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    (a). Why Mn^(2+) compounds are more stable than Fe^(2+) towards oxidation to their +3 state? (b). Calculate the magnetic moment of V^(3+) ion. (c). [Ti(H_2O)_6_^(3+) gives violet coloured aqueous solution but [Mg(H_2O)_6]^(2+) solution is colourless. (d). [Ti(H_2O)_6]^(3+) is coloured whereas [Sc(H_2O)_6]^(3+) is colourless. Why?

    [Sc (H_(2)O)_(6)]^(3+) ion is :-

    [Co(H_(2)O)_(6)]^(3+) complex is

    CuSO_(4).5H_(2)O is blue in colour while CuSO_(4) is colourless. Why ?

    [Co(H_2O)_6]^(3+) is diamagnetic wheras [Co(F_6)]^(3-)] is paramagnetic. Explain.

    A solution of [Ni(H_(2)O)_(6)]^(2+) is green but a solution of [Ni(CN)_(4)]^(2-) is colourless Explain.

    Find CFSE of [Ti(H_2O)_6]^(3+)

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