The solubility of `Mg( OH)_2` in pure water is ` 9.57 xx 10 ^(-3) g L^(-1) ` .Calculate its solubility I ` (g L^(-1))` in 0.02 M Mg `(NO_3)_2` solutions.

Explanation

To calculate the solubility of `Mg(OH)2` in a 0.02 M `Mg(NO3)2` solution, we can follow these steps:

### Step 1: Convert the given solubility from g/L to mol/L
The solubility of `Mg(OH)2` in pure water is given as `9.57 x 10^(-3) g/L`. We need to convert this to moles per liter (mol/L).

1. **Calculate the molar mass of `Mg(OH)2`:**
- Magnesium (Mg) = 24.31 g/mol
- Oxygen (O) = 16.00 g/mol (2 O atoms)
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